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NEET MCQs Reproduction in Organisms Sample
- Clone is two or more individuals which are similar:
a) Genetically b) Morphologically c) Sexually d) Both (A) and (B) - Which of the following is wrongly matched pair?
a) Tuber-Potato b) Rhizome-Ginger c) Bulbil-Agave d) Leaf buds-Banana - Bamboo species flower only in
a) 50-100 yrs b) 25-50 yrs c) 75-100 yrs d) 60-80 yrs - Somaclonal variation appears in plants:
a) Growing in polluted soil or water b) Exposed to gamma rays
c) Raised in tissue culture d) Transformed by recombinant DNA technology - During favourable conditions, ๐ด๐๐๐๐๐ reproduces by:
a) Binary fission b) Multiple fission c) Both of these d) None of these - Asexual reproduction in plants is called
a) Vegetative reproduction b) Syngamy
c) Parthenocarpy d) Parthenogenesis - Identify the following diagram
a. Zoospore in ๐ถโ๐๐๐๐ฆ๐๐๐๐๐๐๐
b. Conidia of ๐๐๐๐๐๐๐๐๐๐ข๐
c. Buds in ๐ป๐ฆ๐๐๐
d. Gemmules in sponge
All the above are
a) Bodies involved in sexual reproduction b) Bodies involved in asexual reproduction
c) Bodies of young ones d) All the above are correct
- The process of release of egg from the ovary is called:
a) Reproduction b) Ovulation c) Menstruation d) Insemination - Juvenile phase in plants, is
a) Vegetative phase b) Reproductive phase c) Growth phase d) Senescence phase - Essential and most critical event in sexual reproduction is
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a) Fertilization b) Fusion of male and female gemetes
c) Division in male and female gametes d) Both (a) and (b)
- The above figure depicts
a) Budding b) Binary fission c) Fission d) Zoospore - Find out correct order of vegetative propagules of plants like potato, ginger, Agave, Bryophyllum and
water hyacinth
a) Offset, bulbil, leaf bud, rhizome and eyes b) Leaf bud, bulbil, offset, rhizome and eyes
c) Eyes, rhizome, bulbil, leaf bud and offset d) Rhizome, bulbil, leaf bud, eyes and offset - Nuclear membrane is absent in:
a) Monera b) Protista c) Fungi d) Plantae - ๐ต๐๐ฆ๐๐โ๐ฆ๐๐๐ข๐ can be propagated vegetatively by:
a) Stem b) Root c) Leaf d) Flower - Self-fertilisation occurs in the
a) Bisexual flower b) Unisexual flower c) Both (a) and (b) d) Monoecious flower - Vegetative propagation in ๐๐๐ ๐ก๐๐ occurs by:
a) Stolon b) Offset c) Runner d) Sucker - One of the followings is not the characteristic feature of cyanobacteria:
a) They are multicellular b) They form colonies
c) They form blooms in polluted water bodies d) They can fix atmospheric nitrogen - The condition, in which, both male and female reproductive organs are found on the same plant, is called
a) Unisexual b) Bisexual c) Both (a) and (b) d) Monoecious - Male gametes are also called
a) Antherozoid b) Sperm c) Egg d) Both (a) and (b) - Bamboo plant flowers only once in their life time, generally 50-100 years, produce larger number of fruits
and die. Blue stretches were formed by flowering of plant. ๐๐ก๐๐๐๐๐๐๐๐กโ๐ข๐ ๐๐ข๐๐กโ๐๐๐๐ in Kerala, Karnataka
and Tamil Nadu. It flowers once in how many years?
a) 15 years b) 12 years c) 20 years d) 48 years - The โeyesโ of the potato tubers are:
a) Root buds b) Flower buds c) Shoot buds d) Axillary buds - Who worked on embryological aspects and popularized the use of embryological characters in taxonomy?
a) P. Guha b) P. Maheshwari c) Ivanovosky d) D. Graaf - Vegetative propagation by leaf takes place in:
a) Ginger b) ๐ต๐๐ฆ๐๐โ๐ฆ๐๐๐ข๐ c) Rose d) ๐ท๐ข๐๐๐๐ก๐ - Binary fission is the mode of asexual reproduction in
a) Amoeba b) Paramecium c) Both (a) and (b) d) Yeast - The part where fertilization of ovum takes place in rabbit, humans and other placental mammals is:
a) Ovary b) Uterus c) Vagina d) Fallopian tube - Grafting is used to propagate plants because:
a) It is faster than seeds
b) It maintains a desired set of genetic characteristics
c) It combines the genetic characteristics of two desirable plants
d) A plant can produce many more scions than seeds - Seasonal breeders are the organisms which reproduces during
a) Favourable season only b) Unfavourable season only
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c) Maturation period d) Juvenile period
- Flower ๐๐ ๐ป๐๐๐๐ ๐๐ข๐ is:
a) Bisexual b) Unisexual c) Neuter d) Very small - Life span of Cow is 20-25 years. What is the life span of horse?
a) 140 years b) 20-30 years c) 100-150 years d) 60 years - โBisexual animals that possess both male and female reproductive organs are called hermaphroditeโ. The
above statement is
a) True b) False
c) Sometimes (a) and sometimes (b) d) Neither (a) and (b) - Regeneration of a plant cell to give rise to new plant is called:
a) Reproduction b) Budding c) Totipotency d) Pleuripotency - Which of the following is hermaphrodite?
a) Ant b) Aphids c) Earthworm d) Cockroach - The separation of single cell from the rest of the callus is:
a) Organ culture b) Tissue culture c) Basal medium d) Nurse tissue - Vivipary is observed in:
a) Banyan b) ๐ต๐๐ฆ๐๐โ๐ฆ๐๐๐ข๐ c) ๐ผ๐๐๐๐๐ d) ๐ โ๐๐ง๐๐โ๐๐๐ - Vegetative propagation in ๐๐๐ ๐ก๐๐ occurs by:
a) Stolon b) Offset c) Runner d) Sucker - ๐
โ๐๐ง๐๐๐ข๐ reproduces asexually by:
a) Conidia b) Spores c) Gemma d) Bulbil - Reproduction is a biological process in which an organism give rise to young ones (offspring) similar to
itself. An organismโs method of reproduction depends upon factors:
a) Habitat b) Internal physiology c) Genitalia d) All of above - Use of stem cutting is common method of vegetative propagation. Juvenile wood grows roots more readily
than mature wood. The superior rooting of juvenile cutting may be due to:
a) Lower ABA contents b) Higher endogenous auxin contents
c) Higher endogenous gibberellins contents d) They being still in the vegetative stage - Events in the diagram are (in sequential order) a) Fission of gametes โ new individual โ zygote
b) Fusion of gametes โ zygote โ new individual (cell 2๐)
c) Fission of gametes โ zygote โ new individual (cell 2๐)
d) Stages in the gametogenesis - Examples of vegetative propagation are
a) Rhizome b) Tuber c) Offset d) All of these - Gametogenesis is the formation of
a) Male gamete b) Female gamete c) Both (a) and (b) d) Spore - Which of the following require water for gamete transfer?
a) Algae, bryophytes and pteridophyte b) Pteriodophyles only
c) Gymnosperms d) Angiosperms - During embryogenesis the zygote undergoes
a) Cell division (mitosis) b) Cell division (meiosis)
c) Cell differentiation d) (a) followed by
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NEET MCQs Inheritance and Variation [Free PDF Download]
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NEET MCQs Inheritance and Variation – Sample
- A haemophilic woman marries a normal man, then
a) All the children will be normal b) All the sons will be haemophilic
c) All the girls will be haemophilic d) Half girls will be haemophilic - Disorder inherited as Mendelโs law of inheritance called
a) Mendelian disorder b) Chromosomal disorder
c) Maternal inheritance d) Polygenic inheritance - The term โgeneโ was coined by
a) Avery b) Bateson c) Johanssen d) Mendel - The phenotypic ratio in the ๐น2 gereration of dihybrid cross, is
a) 9 : 3 : 3 : 1 b) 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1
c) 7 : 1 : 1 : 7 d) 12 : 8 : 4 - Chromosome is made up of
a) DNA +pectin b) RNA +DNA c) DNA +histone d) Only histone - Select the incorrect statemant from the following.
a) Linkage is an exception to the principle of
independent assortment in heredity
b) Galactosemia is an inborn error of metabolism
c) Small population size result in random genetic
drift in a population
d) Baldness is a sex-limited trait - A pure tall and a pure dwarf plant were crossed to produced offsprings. Offsprings were self crossed, then
find out the ratio between true breeding tall to true breeding dwarf?
a) 1 : 1 b) 3 : 1 c) 2 : 1 d) 1 : 2 : 1 - Exposure of X-rays enhances the frequency of
a) Linkage b) Crossing over
c) Pairing of chromosome d) Segregation - A self-fertilizing trihybrid plant forms
a) 8 different gametes and 64 different zygotes b) 4 different gametes and 16 different zygotes
c) 8 different gametes and 16 different zygotes d) 8 different gametes and 32 different zygotes - Genotype is the
a) Genetic constitution b) Genetic constitution of the phenotype
c) Trait expressed d) Expressed genes - Failure of cytokinesis after โฆAโฆ stage of cell division results in an increase in a whole set of chromosomes
in an organism called โฆBโฆ
a) A-prophase, B-polyploidy b) A-metaphase, B-polyploidy
c) A-anaphase, B-polyploidy d) A-telophase, B-polyploidy - In previous question find out total seeds (plants) having round seed texture
a) 12 b) 10 c) 9 d) 11 - The ratio 1 : 1 : 1 : 1 is obtained from a cross between the parents
a) RRYYรrryy b) RRYYรrryy c) RRYYรRryy d) RrYyรrryy - Which of the following terms represent a pair of contrasting characters?
a) Homozygous b) Heterozygous c) Allelomorphs d) Codominant genes
NEET MCQs Inheritance and Variation – Page| 2
- Harmful mutation does not get eliminated from the gene pool because they are mainly
a) Dominant, which have beneficial effect on population and carried by heterozygous individuals
b) Dominant, which have beneficial effect on population and carried by homozygous individuals
c) Carried from one generation to another generation through autosomal chromosomes
d) They show genetic drift - Incomplete linkage is โฆAโฆ . Complete linkage is โฆBโฆ . Choose correct option for A and B
a) A-common, B-rare b) A-rare, B-common
c) A-impracticle, B-practicle d) A-practicle, B-impracticle - Mendelism was rediscovered by
I. Morgan
II. De Vries
III. Correns
IV. Tschermark
Choose the correct option
a) I, III and IV b) I, II, III and IV c) II, III and IV d) I, II and III - In gynandromorphs,
a) Some cells of body contain XX and some cells with genotype XY
b) All cells have XX genotype
c) All cells have XY genotype
d) All cells with genotype XXY - Example of interagenic gene interaction is/are
a) Incomplete dominance b) Codominant
c) Multiple alleles d) All of the above - If a cross between two individuals produces offspringe with 50% dominant character (A) and 50%
recessive character (a),then the genotypes of parents are
a) Sex linked genes b) Pseudoallelic genes
c) Intermediate inheritance d) Dominant and recessive genes - Which is correct about traits choosen by Mendel for his experiment on pea plant?
a) Terminal pod was dominant b) Constricted pod was dominant
c) Green coloured pod was dominant d) Tall plants were recessive - Codominance is found in
a) Plants b) Animal c) Both (a) and (b) d) Prokaryote - During Mendelโs investigation, it was first time that โฆAโฆ and โฆBโฆ were applied in biology. Here A and B
refers to
a) A-statistical analysis; B-mathematical logic
b) A-statistical analysis; B-physical logic
c) A-statistical analysis; B-chemistry logic
d) A-statistical analysis; B-simple logic - The chromosomal denotation for heterogametic female and homogametic male are
a) ZW and ZZ b) ZO-ZZ c) XX-XO d) Both (a) and (b) - Pure tall plants are crossed with pure dwarf plants. In the F1-generation, all plants were tall. These tall
plants of F1-generation were selfed and the ratio of tall to dwarf plants obtained was 3: 1. This is called
a) Dominance b) Inheritance c) Codominance d) heredity - The best method to determine the homozygosity and heterozygosity of an individual is
a) Self-fertilisation b) Back cross c) Test cross d) Inbreeding - A medical technician, while observing a human blood smear under the microscope notes the presence of a
Barr body close to the nuclear membrane in the WBC. This indicates that the person under investigation is
a
a) Colourblind b) Haemophilic c) Normal female d) Normal male - Find out ๐ด,๐ต and ๐ถ in the diagram given below in
NEET MCQs: Inheritance & Variation – Page| 3
a) A-Male, B-Female, C-Gametes b) A-Male, B-Female, C-Sperm
c) A-Female, B-Male, C-Gametes d) A-Gametes, B-Male, C-Female
- In Turnerโs syndrome
a) Female is fertile b) Male is fertile c) Female is sterile d) Male is sterile - The most likely reason for the development of resistance against pesticides in insect damaging a crop is
a) Random mutations b) Genetic recombination
c) Directed mutations d) Acquired heritable changes - Lampbrush chromosomes sre seen in
a) Interphase b) Zygotene c) Diplotene d) metaphase - In case of incomplete dominance, what will be the phenotypic ratio of ๐น2generation?
a) Histones b) Hydrocarbons c) Polynucleotides d) Lipoproteins - Examples of dissimilar sex chromosomes are given below
I. XX โ XY โ I
II. XX โ XO โ II
I and II in the above statement can be
I II a) Man and most
insect
Cockroach and
roundworms
b) Cockroach and
roundworms
Man and most
insect
c) Butterfly Fishes
d) Bird Reptiles
- Mutations, which alter nucleotide sequence within a gene are
a) Frameshift mutation b) Base pair substitutions
c) Both (a) and (b) d) None of these - The ๐น1generation has all tall, and ๐น2ratio is 3 : 1, it proves
a) Law of dominance b) Independent assortment
c) Law of segregation d) linkage - Mendelโs law were true for situation in which
a) Alleles are affected by their environment b) Alleles shows complete dominance
c) Alleles of a gene alter the affect of a different gene d) A given character is determined by more than one
gene - Blood group-O has
a) No antibodies b) No antigens c) a or b antibodies d) A and B antigens - Wilson detected the colour blindness disease in
a) 1921 b) 1911 c) 1912 d) 1910 - In a dihybrid cross between RRYY and rryy parents, the number of RrYy genotypes in ๐น2generation will be
a) 4 b) 3 c) 2 d) 1 - If a cross between two individuals produces offspringe with 50% dominant character (A) and 50%
recessive character (a),then the genotypes of parents are
a) Genic interactions controlling a character b) Multiple genes controlling a character
c) Expression of many characters by a single gene d) Alternative forms of a gene at a given locus - A women with albinic father marries an albinic man.the proportion of her progeny is
a) 2 normal : 1 albinic b) All normal
c) All albinic d) 1 normal : 1 albinic
NEET MCQs: Inheritance & Variation – Page| 4
- When one sex chromosome is lacking in female and males are homogametic, in that condition, the sex
chromosomal representation is
a) ZO-ZZ b) XY-XX c) XX-XO d) ZW-ZZ - Some individuals with blood group โA may inherit the genes for blonde hair, while other individuals with
blood group โ A may the gene for brown hair. This can be best explained by the principle of
a) Dominance b) Multiple alleles
c) Independent assortment d) Incomplete dominance - In bugs and cockroaches, the sex determination takes place by
a) XX and XO chromosomes b) XX and XY chromosomes
c) ZZ-ZW chromosomes d) ZO-ZZ chromosomes - The two โฆAโฆ separate and pass into two daughter nuclei and cells during mitosis. Similarly, each โฆBโฆ
replicates, with one pair passing into each daughter cell during mitosis. This maintains the similar โฆCโฆ of
all the cells.
Find out correct option for A, B and C
a) A-chromatid, B-allele pair, C-morphology b) A-chromatid, B-allele pair, C-genetic composition
c) A-organ, B-organ pair, C-individuality d) A-unlinked gene, B-linked gene, C-morphology - The shape of chromosome is determined by
a) Centrosome b) Centromere c) Chromomere d) telomere - Mendel was a
a) Austrian biology teacher b) Austrian monk
c) Austrian scientist d) Austrian mathematician - Who clearly proved and define linkage?
a) Morgan b) Castle c) Bateson d) Punnett - Improvement of human race through hereditary qualities is called
a) Euthenics b) Human heredity c) Human demography d) Eugenics - Test cross involves
a) Crossing between two genotypes with recessive trait
b) Crossing between two F1-hybrids
c) Crossing the F1-hybrid with a double recessive genotype
d) Crossing between two genotypes with dominant trait - When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in the
resulting seed is
a) Tetraploidy b) Pentaploidy c) Diploidy d) Triploidy - Colour blindness is
a) Sex-linked recessive disease
b) Sex-linked dominant disease
c) Autosomal dominant disease
d) Autosomal recessive disease - A condition, where a certain gene is present in only a single copy in a diploid cell, is called
a) Four different types of gametes produed by the ๐น1
dihybrid b) Homozygous condition of the ๐น1-dihybrid
c) Four different types of ๐น1-dihybrids d) Four different types of gametes produed by the
๏ฟฝ
๏ฟฝ1-parent - If the blood group of a child is A and of mother is B, then the genotype of mother and father may be
a) BBรAA b) ABรAB c) BOรOO d) BOรAO - symbol in pedigree analysis represents
a) Still birth b) Still death c) Still carrier d) Still mating - Which amino acids are present in histones?
a) Lysine and histidine b) Valine and histidine
NEET MCQs: Inheritance & Variation – Page| 5
c) Arginine and lysine d) Arginine and histidine
- Monosomic trisomy are represented as
a) 2๐โ1+1 b) 2๐โ1โ1 c) 2๐โ1 d) 2๐+1+1 - Which is a sex-influenced disease?
a) Baldness in male b) Haemophilia
c) Xeroderma pigmentosa d) Downโs syndrome - Thalassaemia is
a) Autosomal recessive disease b) Autosomal dominant disease
c) Sex-linked dominant disease d) Sex-linked recessive disease - Mutation is phenomena which results in alternation of
a) Sequence b) Carbohydrates c) Proteins d) Fat - A man with normal vision whose father was colourblind marries with women whose father was also
colourblind. Suppose their first child is daughter then what are the chances of this child to be colourblind?
a) 100% b) 25% c) 50% d) 0% - Gamete mother cells of the chromosome 44 + XY suffers from non-disjunction at first meiotic division.
Which of the following set of gametes would result?
a) 22 + XX, 22 + XY, and 22, 22 b) 22 + XY, 22 + XY, and 22, 22
c) 22 + X, 22 + Y, and 22 + Y, 22 d) 22 + X, 22 + XY, and 22 + Y, 22 + Y - Law of Mendel, which is not completely applicable is?
a) Codominance b) Law of segregation
c) Law of independent assortment d) Law of dominance - Low pitched voice, beared and moustaches, belong to the
a) Sex limited traits b) Sex linked trait c) Nullisomic traits d) Sex influenced traits - Multiple allele can be manifested only when there is the study of
a) Individual organism b) Genus c) Population d) Phylum - ๐๐๐๐๐ก๐๐๐๐ ๐ ๐ฆ๐๐ฃ๐๐ ๐ก๐๐๐ flowers only during long days and ๐.๐ก๐๐๐๐๐ข๐ flowers only during short days, if
raised in the laboratory under different photoperiods, they can be induced to flower at the same time and
can be cross fertilized to produce self-fertile offspring. What is the best reason for considering N. sylvestris
and N. tobaccum to be separate species?
a) They are physiologically distinct b) They are morphologically distinct
c) They cannot interbreed in nature d) They are reproductively distinct - The following diagram shows two types of chromosomal mutations
Give the name or type of mutation in respect to A and B
a) A-Duplication, B-Substitution b) A-Duplication, B-Deletion
c) A-Inversion, B-Deletion d) A-Inversion, B-Substitution
- How many different kinds of gametes will be produced by a plant having the genotype AABbCC?
a) Three b) Four c) Nine d) Two - Downโs syndrome and Turnerโs syndrome occur in human beings due to
a) Monosomic and nullisomic conditions respectively b) Monosomic and trisomic conditions respectively
c) Trisomic and monosomic conditions respectively d) Trisomic and tetrasomic conditions respectively - What are all the chances of colourblind daughters of a normal man marrying normal women whose father
was colourblind?
a) All sons are normal and all daughters are
colourblind
b) Both the sons and daughters are phenotypically
normal
NEET MCQs: Inheritance & Variation – Page| 6
c) All the sons are colourblind and all daughters are
normal
d) 50% sons are colourblind and all daughters are
phenotypically normal
- In males, pattern baldness is related to both autosomal genes as well as excessive secretion of
a) Oestrogen b) Growth hormone c) Testosterone d) Inhibits - Which of these is not a Mendelian disorder?
a) Cystic fibrosis b) Sickle-cell anaemia c) Colourblindness d) Turnerโs syndrome - Which of the following is not true of haemophilia?
a) Royal disease b) Bleederโs disease
c) X-linked disorder d) Y-linked disorder - If heterozygous dominant (tT) crossed with homozygous dwarf plant, then the percentage of progeny
having dwarf character is
a) 60% b) 40% c) 50% d) 70% - Mutations are generally induced by means of
a) ๐ผโ๐๐๐ฆ๐ b) ฮฒโ๐๐๐ฆ๐ c) ๐พโ๐๐๐ฆ๐ d) UV radiations - Two crosses between the same pair of genotypes or phenotypes, in which the sources of the gametes are
reversed in one cross, is known as
a) Dihybrid cross b) Reverse cross c) Test cross d) Reciprocal cross - A hereditary, disease, which is never passed on from father to son is
a) X-chromosomal linked disease b) Autosomal linked disease
c) Y-chromosomal linked disease d) None of the above - Bateson used the term coupling and repulsion for linkage and crossing over. Choice the correct coupling
and repulsion combination
Coupling Repulsion a) AABB, aabb AAbb, aaBB
b) AABB, aabb AABB, AAbb
c) AAbb, aaBB AaBb, aabb
d) aaBB, aabb AABB, aabb
- In blood group typing in human, if an allele contributed by one parent is IAand an allele contributed by the
other parent is i, the resulting blood group of the offspring will be
a) A b) B c) AB d) O - A person having 45 chromosomes and Y-chromosome absent. Is suffering from
a) Downโs syndrome b) Klinefelterโs syndrome
c) Turnerโs syndrome d) gynandromorph - Linkage and crossing over are
a) Same phenomena b) Different phenomena
c) Opposite phenomena d) Identical phenomena - The modern concept of gene is
a) A segment of DNA, capable of crossing over b) Functional unit of DNA
c) A segment of RNA d) A segment of chromosome - Females in haplodiploidy sex determination are
a) N b) 2n c) 1
2
n d) 3n - Using imprints from a plate with complete medium and carrying bacterial colonies, you can select
streptomycin resistant mutants and prove that such mutations do not originate as adaptation. These
imprints need to be used
a) Only on plates with streptomycin b) On plates with minimal medium
c) Only on plates without streptomycin d) On plates with and without streptomycin - Phenylketonuria, Huntingtonโs disease and sickle cell anaemia are caused respectively due to disorders
associated with
a) Chromosome-7, chromosome-11 and chromosome-12
b) Chromosome-11, Chromosome-4 chromosome-12
c) Chromosome-7, chromosome-12 and chromosome-11
d) Chromosome-12, chromosome-4 and chromosome-11
Page| 7
- The arrangement of genes on chromosome is
a) Linear b) Oviod c) Diffused d) Spiral - When two genetic loci produce identical phenotypes in ๐๐๐ and ๐ก๐๐๐๐ position, they are considered to be
a) Pseudoalleles b) Multiple alleles
c) The part of same gene d) Different genes - Which of the following matches correctly?
a) Factor โII – Thromboplastin b) Factor โIII – Prothrombin
c) Factor โVIII – Antihaemophilic globulin d) Factor โXII – Haemophilic - The longest chromosomes is seen in
a) Allium b) Lilium c) Trillium d) Zea mays - Mendel observed that โฆ.. generation shows always phenotype of dominant parent
a) F4 b) F2 c) F1 d) F0 - โฆAโฆ genes are those which occurs on the same chromosome and โฆBโฆ genes are those, which are present
on different chromosome.
Choose correct choice for A and B
a) A-linked; B-unlinked gene b) A-unlinked; B-linked
c) A-identical; B-non-identical d) A-non-identical; B-identical - Allelic sequence variations where more than one variant (allele) at a locus in a human population with a
frequency greater than 0.01 is refered to as
a) Incomplete dominance b) Multiple allelism
c) SNP d) DNA polymorphism - The possibility of a female becoming a haemophilia is โฆAโฆ rare because mother of such a female has to be
at least โฆBโฆ and the father should be โฆCโฆ
Choose the correct option for A, B and C
a) A-extremely, B-carrier, C-haemophilic
b) A-extremely, B-carrier, C-carrier
c) A-extremely, B-haemophilic, C-carrier
d) A-extremely, B-haemophilic, C-haemophilic - If the foetus is Rh+ and mother is Rhโ, then
a) Foetus will transmit antigen to mother blood
b) Foetus will transmit antibody to mother blood
c) Foetus is attacked by antibodies to mother blood
d) Foetus is attacked by antigen to mother blood - The most popularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because โOโ
in it refers to having
a) Other antigens besides A and B on RBCs b) Over dominance of this type on the genes for A
and B types
c) One antibody onlyโeither anti-a or antiโb on the
RBCs
d) No antigens A and B on RBCs - Alleles are
a) Alternate forms of a gene b) Homologous chromosome
c) Pair of sex chromosome d) None of the above - Telomere repetitive DNA sequences control the function of eukaryotic chromosomes because they
a) Act as replicons b) Are RNA transcription initiator
c) Help chromosome pairing d) Prevent chromosome loss - Genotypic and phenotypic ratios remains the same in
a) Sex-linked genes b) Pseudoallelic genes
c) Intermediate inheritance d) Dominance and recessive genes - Mendelian disorder may be of
a) Recessive b) Dominant c) Both (a) and (b) d) Canโt be determined
NEET MCQs: Inheritance & Variation Page| 8
- Sickle โcell anaemia has not been eliminated from the African population because it
a) Is controlled by recessive genes b) Is not a fatal disease
c) Provides immunity against malaria d) Is controlled by dominant genes - A condition characterized by not having an exact number of chromosomes in a multiple of haploid set is
called
a) Polyploidy b) Synploidy c) aneuploidy d) None of these - Choose correct option for ๐ด,๐ต,๐ถ and ๐ท a) A-tt, B-TT, C-TT, D-TT b) A-Tt, B-Tt, C-Tt, D-Tt
c) A-TT, B-TT, C-Tt, D-TT d) A-Tt, B-Tt, C-Tt, D-TT - When a cross is conducted between black feathered hen and a white feathered cock, blue feathered fowls
are formed. When these fowls are allowed for interbreeding, in F2- generation, there are 20 blue fowls.
What would be the number of black and white fowls?
a) Black 20, white 10 b) Black 20, white 20 c) Black 10, white 10 d) Black 10, white 20 - Chromosomes are made up of
a) DNA are protein b) RNA and DNA c) DNA and histone d) Only histones - In pedigree analysis, the square, blackened and horizontal lines represents
a) Female, healthy individual, parents b) Female, affected individual, parents
c) Male, affected individual, parents d) Male, affected individual, progeny - Following pedigree chart shows a) Character is carried by Y-chromosome b) Character is sex-linked recessive
c) Character is sex-linked dominant d) Character is recessive autosomal - Mr. Sidd is suffering from hypertrichosis and phenylketonuria. His father is heterozygous for
phenylketonuria. The probability of Siddโs sperm having one recessive autosomal allele and holandric
gene is
a) 1
2 b) 1
8 c) 1
10 d) 1
4 - F3-generation is obtained by
a) Selfing of F1 b) Selfing of F2 c) Crossing of F1 and F2 d) None of these - In which one of the following, complementary gene interaction rato of 9 : 7 is observed?
a) Fruit shape in Shepherdโs purse b) Coat colour in mouse
c) Feather colour in fowl d) Flower colour in pea - Starch synthesis gene in pea plant is the example of
a) Single gene produce more than one effects
b) Multiple genes produce more than one effects
c) Two genes produce more than one effects
d) Multiple genes produce less than one effects - In ๐ท๐๐๐ ๐๐โ๐๐๐ , the sex is determined by
a) The ratio of pairs of X-chromosomes to the pairs of autosomes
b) Whether the egg is fertilized or develops parthenogenetically
NEET MCQs: Inheritance & Variation Page| 9
c) The ratio of number of X-chromosomes to the set of autosomes
d) X and Y-chromosomes
- The 1 : 2 : 1 ratio with the pink flower in the F2-generation indicate the phenomenon of
a) Dominance b) Codominance
c) Incomplete dominance d) Segregation - Sexual reproducation leads to
a) Genetic recombination b) Polyploidy
c) Aneuploidy d) Euploidy - Husband has blood group-A and wife has blood group-B. What is the blood group of children?
a) A b) B c) AB d) A, B, AB and O - Study the following figure and find out the most probable position at which the crossing over takes place a) w and W b) X and y c) y and Z d) w and z
- Given diagram shows certain type of traits in human. Which one of the following option could be an
example of this pattern? a) Haemophilia b) Anaemia c) Phenylketonuria d) Thalassaemia - In case of incomplete dominance, what will be the phenotypic ratio of ๐น2generation?
a) 3 : 1 b) 1 : 2 : 1 c) 1 : 1 : 1 : 1 d) 2 : 2 - Haemophilia, a X-linked recessive disease is caused due to deficiency of
a) Blood plasma and vitaminโK b) Blood platelets and haemoglobin
c) Lack of clotting material and vitamin-K d) All of the above - All of this obeys Mendelโs laws except
a) Codominance b) Independent assortment
c) Dominance d) Purity of gametes - in ฮฒ-thalassaemia, the affected chromosome is
a) 16th b) 14th c) 13th d) 19th - In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a
green seeded plant, what ratio of yellow and green seeded plants would you expect in ๐น1generation?
a) 50 : 50 b) 9 : 1 c) 1 : 3 d) 3 : 1 - Who was fly men of genetics?
a) Sutton b) Pasteur c) Robert Hooke d) TH Morgan - Mendelโs contribution for genetic inheritance was
a) The idea that genes are found on chromosomes
b) Providing a mechanism that explains patterns of inheritance
c) Describing how genes are influenced by the environment
d) Determining that the information contained in DNA codes for proteins - The genotypic ratio of a monohybrid cross in F2-generation is
NEET MCQs: Inheritance & Variation Page| 10
a) 3 : 1 b) 1 : 2 : 1 c) 2 : 1 : 1 d) 9 : 3 : 3 : 1
- Baldness is more common in men than in woman. It could be explained on the basis that
a) Genes of baldness are located on X-chromosomes only
b) Baldness genes are located on Y-chromosomes
c) Genes of baldness are autosomal but influenced by androgens
d) None of the above - How many pairs of contrasting characters in pea pod were chosen by Mendel?
a) 3 b) 5 c) 7 d) 9 - A mutagen pollutant is
a) Organophosphates b) Resins
c) Chlorinated hydrocarbons d) Nitrogen oxides - Both chromosome and gene (Mendelian factors) whether dominant or recessive are transmitted from
generation to generation in which form
a) Changed b) Unaltered form c) Altered form d) Disintegrated - Pedigree analysis is very important in human beings because
a) It helps genetic counselers to avoid disorders
b) It shows origin of traits
c) It shows the flow of traits in family
d) All of the above - Genes when present in homozygous condition results in non โ viable progeny, the factor responsible for
such conditions are
a) Polygenes b) Linked genes c) Lethal genes d) Epistatic genes - Turnerโs syndrome caused due to the absence of
a) One X-chromosome (44 with XO) b) One Y-chromosome
c) One X-and Y-chromosome d) Two X-chromosome - The recessive genes located on X-chromosome in humans are always
a) Lethal b) Sub-lethal c) Expressed in males d) Expressed in females - Strength of the linkage between the two genes is
a) Proportionate to the distance between them
b) Inversely proportionate to the distance between them
c) Depend on the chromosomes
d) Depend upon the size of chromosomes - Fruitfly is excellent model for genetics because of
I. Small life cycle (two week)
II. Can be feed on simple synthesis medium
III. Single mating produce large number of progeny
IV. Clear differentiation of sexes
V. Many heredity variation can be seen with low power microscopes
Choose the correct option
a) I, II and III b) III, IV and V c) I, IV and V d) All of these - In Guinea pigs, black short hair (BBSS) is dominant over white long hair (bbss). During a dihybrid cross,
the ๐น2-generation individuals with genotypes BBSS, BbSS, BBSs and BbSs are in the ratio of
a) 9 : 3 : 3 : 1 b) 4 : 2 : 1 : 2 c) 1 : 2 : 1 : 2 d) 1 : 2 : 2 : 4 - When both parents are of blood type AB, they can have children with
a) A, B, AB and O blood types b) A, B, and AB blood types
c) A and B blood types d) A, B and O blood types - Test cross is
a) Recessive F1-plant crosses with dominant F2-plant
b) Recessive F2-plant crosses with dominant F3-plant
c) Dominant F2-plant crosses with recessive parent plants
d) Dominant F2-plant crosses with heterozygous parent plants
Page| 11
- The phenomenon of a single gene regulating several phenotypes is called
a) Multiple allelism b) epistasis
c) Incomplete dominance d) Pleiotropism - If two pea plants having red (dominant) coloured flowers with unknown genotypes are crossed, 75% of
the flowers with unknown genotypes are crossed, 75% of the flowers are red and 25% are white. The
genotypic constitution of the parents having red coloured flowers will be
a) Both homozygous b) One homozygous and other heterozygous
c) Both heterozygous d) Both hemizygous - A woman has a haemophilic son and three normal children. Her genotype and that of her husband with
respect to this gene would be
a) XX and XhY b) XhXh and XhY c) XhXh and XY d) XhX and XY - The proportion of plants that were dwarf and tall in F2- generation ofo Mendel experiment
a) 1
4th and 3
4th b) 3
4th and 1
4th c) 2
3rd and 1
3rd d) 1
3rd and 4
3rd - Night blindness is
a) Genetic disease b) Nutritional deficiency disease
c) Generally found in male d) Generally found in female - Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY
and rryy genotypes are hybridized, then ๐น2-segregation wii show
a) 1 : 2 : 1 b) 3 : 1 c) 9 : 3 : 3 : 1 d) 1 : 1 : 1 - Who argued that pairing and separation of chromosomes would lead to the segregation of a pair of factor
they carried?
a) Sutton b) Boveri c) Both (a) and (b) d) Morgan - Sex chromosomes of male are
a) Homozygous b) Heterozygous c) Hemizygous d) autosomes - Trisomy of which chromosome is involved in Downโs syndrome?
a) 15th b) 21st c) 20th d) 19th - Which of the following symbols are used for representing chromosome of birds?
a) ZZ-ZW b) XX-XY c) XO-XX d) ZZ-WW - Sudden and heritable change in a character of an organism is called
a) Mutation b) Heterosis c) Inbreeding d) selection - Heterozygous purple flower is crossed with recessive white flower. The progeny has the ratio
a) All purple b) All white
c) 50% purple, 50% white d) 75% purple, 25% white - The Mendel crossed true breeding tall and dwarf plant varieties in his experiment. The tall character was
dominant and recessive character was dwarf. The recessive character was appeared in
a) F1 b) F2 c) F3 d) F2 and F3 - Night blindness can be corrected by giving vitamin- โฆAโฆ but colour blindness canโt be cured because it is
โฆBโฆ disease.
Choose the correct option for A and B
a) A-A; B-genetic b) A-B; B-autosomal c) A-C; B-non-genetic d) A-D; B-genetic - Heredity is
a) Transmission of characters b) Mixing of characters
c) Blending of inheritance d) Deleting of characters - Which of these statements about Huntingtonโs disease is true?
a) Genetic tests to detect the presence of the allele responsible for Huntingtonโs disease do not exist at this
time
b) The onset of Huntingtonโs disease is typically between birth and three years of age
c) There is currently no effective treatment of Huntingtonโs disease
d) Huntingtonโs disease is caused by the expression of a recessive allele
Page| 12
- Centromere is required for
a) Transcription b) Crossing over
c) Cytoplasmic cleavage d) Movement of chromosomes towards poles - Which of the following condition in humans is correctly matched with its chromosomal
abnormality/linkage?
a) Klinefelterโs syndrome โ44 autosomes + XXY b) Colour blindness โY- linked
c) Erythroblastosis foetalis โX- linked d) Downโ s syndrome โ 44 autosomes+ XO - Rrrr progeny : Red (dominant) flowered heterozygous crossed with white flower
a) 350โredโถ350โwhite b) 450โredโถ250โwhite
c) 380โredโถ250โwhite d) None of these - A hereditary disease which is never passed on form father to son is
a) X- chromosomal linked disease b) Autosomal linked disease
c) Y- chromosomal linked disease d) None of the above - A man with blood group-B marries a woman with blood-A and their first child is having blood group-B.
What is the genotype of child?
a) IaIb b) IaIo c) IbIo d) IbIb - Linked gene are present on
a) Same chromosome b) Different chromosome
c) Heterologous chromosome d) Paired chromosome - The structure that become double in synthesis phase of cell division is/are
a) RNA b) Centriole c) DNA d) None of these - Genetics is the branch of biology which deals with
a) Variation b) Inheritance c) Both (a) and (b) d) Study of characters - Giant chromosomes are found inside
a) nucleus of man b) oocytes of frog
c) salivary glands of silk moth d) salivary glands of Drosophila - Who is known as father of physiological genetics or father of biochemical genetics?
a) Slatyer b) Charles Elton c) Taylor d) Archibald Garrod - The graphical representation to calculate the probability of all possible genotypes of offspring in a genetic
cross, is called
a) Pedigree analysis b) Karyotype c) Punnett square d) Chromosome map - Rh factor can produce disease
a) AIDS b) Turnerโs syndrome
c) Erythroblastosis foetalis d) Sickle-cell anaemia - To determine heterozygousity of a cross, one has to perform
a) Back cross b) Reciproacal cross c) Test cross d) Any of these - Which of the following type of mutation involves the reverse order of genes in a chromosome?
a) Deletion b) Duplication
c) Inversion d) Reciprocal translocation - The chromosomal number in the meiocytes of housefly is
a) 8 b) 12 c) 21 d) 23 - The alternate forms of a gene is called
a) Recessive character b) Dominant character
c) Alleles d) Alternative gene - Haemophilia is related to
a) Albinism b) Sickle-cell anaemia c) Colour blindness d) thalassemia - Identify a Mendelian disorder from the following.
a) Downโs syndrome b) Turnerโs syndrome
Page| 13
c) Phenylketonuria d) Klinefelterโs syndrome
- When a tall plant with round seeds (TTRR) crossed with a dwarf plant with wrinkled seeds (ttrr), the ๐น1
generation consists of tall plants with round seeds. What would be the proportion of dwarf plant with
wrinkled seeds in ๐น1-generation?
a) 1
4 b) 1
16 c) 0 d) 1
2 - The term โGeneticsโ was proposed by
a) Mendel b) Bateson c) Motgan d) Johanssen - Sex chromosomes are also known as
a) Autosomes b) Allosomes c) Genome d) karyotype - Mendel obtained recessive character in F2 by โฆAโฆ the โฆBโฆ plants. Here ๐ด and ๐ต refers to
a) A-self-pollinating; BโF1 b) A-self-pollinating; BโF2
c) A-cross-pollinating; BโF1 d) A-cross-pollinating; BโF2 - In a family father had a trait but mother did not. All their sons and daughter had this trait. The same trait
was found in some grand daughters, through daughter were married to the normal persons.
Choose the correct pedigree chart for the condition
a)
b)
c)
d)
- If genes of an allelic pair are not-same. This condition is called
a) Homozygous b) Heterozygous c) Diallelic d) Polyallelic - Which type of pollination method was adopted by Mendel in his experiment?
a) Artificial b) Cross pollination c) Natural d) Both (a) and (b) - Select the correct statement from the ones given below with respect to dihybrid cross.
a) Tightly linked genes on the same chromosome
show higher recombinations
b) Genes far apart on the same chromosome show
very few recombinations
c) Genes loosely linked on the same chromosome
show similar recombinations as the tightly linked
ones
d) Tightly linked genes on the same chromosome
show very few recombinations - Grain colour in wheat is determined by three pairs of polygene. Following the cross
AABBCC(dark colour)รaabbcc(light colour) , in ๐น2 generation. What proportion of the progeny is likely to
resemble either parent?
a) Half b) Less than 5 per cent c) One โthird d) None of these - Chromosomal abbreviation commonly found in the
a) Cancer cells b) Normal cells c) Healthy cells d) Autosomal cells - In short horned cattle, genes for red( R) and white( r) coat colour occur. Cross between red (RR) and
white (rr) produced (Rr) roan. This is an example of
a) Incomplete dominance b) Codominance
c) Complementary genes d) Epistasis - Female is haemophilic definitely if
a) Mother is carrier b) Father is carrier
c) Father is affected d) Both mother and father affected
Page| 14
- Polyploidy leads to rapid formation of new species because of
a) Isolation b) Development of multiple sets of chromosomes
c) Mutation d) Genetic recombination - Law of segregation is also called law of
a) Probability b) Purity of gametes
c) Independence of gametes d) Punnett hypothesis - Test cross is a cross between
a) HybridรDominant parent b) HybridรRecessive parent
c) HybridรHybrid parent d) Two distantly related species - XX and XY chromosomal sex determination, females are
a) Homogametic b) Heterogametic
c) Can not determine d) All of the above - Heterogametic male condition does not occur in
a) Birds b) Humans c) Drosophila d) Honey bee - In a typical Mendelian cross which is a dihybrid cross, one parent is homozygous for both dominant traits
and another parent is homozygous for both recessive traits. In the ๐น2 generation, both parental
combinations and recombinations appear. The phenotypic ratio of parental combinations to
recombinations, is
a) 10:6 b) 12:4 c) 9:7 d) 15:1 - The genotype of a plant showing the dominant phenotype can by
a) Test cross b) Dihybrid cross c) Pedigree analysis d) Back cross - If a man who is colourblind marries a women, who is pure normal for colour vision, the chances of their
sons have colour blindness is
a) 100% b) 50:50 c) 0% d) 75 : 25 - When a tall pea plant (TT) is crossed with dwarf plant (tt) what will be the F2-generation?
a) All tall plants b) All dwarf plants
c) Both tall and dwarf plants in 1 : 1 ratio d) Both tall and dwarf plants in 3 : 1 ratio - Broadly the genetic disorders may be classified in โฆAโฆ group Mendelian disorder and โฆBโฆ disorders.
Mendelian disorder are mainly determined by โฆCโฆ in single gene.
Choose the correct option for A, B and C
a) A-two, B-chromosomal, C-genetic b) A-two, B-chromosomal, C-inversion
c) A-two, B-chromosomal, C-alteration d) A-three, B-chromosomal, C-deficiency - โฆAโฆ individual show โฆBโฆ phenotype but they are the โฆCโฆ of the disease as there is 50% probability of
transmission of mutant gene to its progeny
Choose the correct option for A, B and C
a) A-homozygous, B-affected, C-carrier b) A-homozygous, B-unaffected, C-carrier
c) A-heterozygous, B-unaffected, C-carrier d) A-heterozygous, B-affected, C-carrier - If male is TT and female is tt than they contribute pollen and egg respectively with
a) T and T gametes b) tt and TT gametes c) TT and tt gametes d) T and t gametes - Number of linkage group in Pisum sativum is
a) 2 b) 5 c) 7 d) 9 - In Mendelโs experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr),
yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the
F2- generation of the cross RRYYรrryy?
a) Only round seeds with green cotyledons b) Only wrinkled seeds with yellow cotyledons
c) Only wrinkled seeds with green cotyledons d) Round seeds with yellow cotyledons and wrinkled
seeds with yellow cotyledons - BB = for black colour alleles
bb = for brown colour alleles
Offspring of a cross between a black mouse and brown mouse allowed to interbreed than find out the
percentage of black coat in them
a) 75%
b) 50%
c) Cross is not possible because black and brown mouse are different species
d) 100%
NEET MCQs: Inheritance & Variation – : ANSWER KEY :
๏ปฟ
1) b 2) a 3) c 4) a
5) c 6) d 7) a 8) b
9) a 10) b 11) d 12) a
13) d 14) c 15) a 16) a
17) c 18) a 19) d 20) c
21) c 22) a 23) a 24) d
25) a 26) b 27) c 28) a
29) c 30) c 31) c 32) c
33) a 34) c 35) c 36) b
37) b 38) d 39) a 40) d
41) d 42) a 43) c 44) a
45) b 46) b 47) b 48) a
49) d 50) c 51) a 52) a
53) a 54) d 55) b 56) c
57) a 58) a 59) a 60) a
61) d 62) b 63) c 64) d
65) c 66) c 67) b 68) d
69) c 70) d 71) c 72) d
73) d 74) c 75) c 76) d
77) a 78) a 79) a 80) c
81) c 82) b 83) b 84) a
85) d 86) a 87) a 88) c
89) c 90) c 91) a 92) d
93) a 94) a 95) d 96) a
97) d 98) c 99) c 100) c
101) c 102) b 103) c 104) c
105) c 106) a 107) a 108) b
109) d 110) a 111) c 112) c
113) a 114) d 115) d 116) a
117) b 118) c 119) a 120) d
121) a 122) a 123) b 124) b
125) c 126) a 127) c 128) b
129) d 130) c 131) a 132) c
133) b 134) d 135) d 136) b
137) c 138) d 139) c 140) d
141) a 142) b 143) a 144) c
145) b 146) b 147) a 148) a
149) c 150) d 151) a 152) a
153) c 154) d 155) a 156) a
157) a 158) c 159) a 160) c
161) c 162) c 163) d 164) c
165) c 166) c 167) c 168) b
169) c 170) c 171) c 172) c
173) b 174) b 175) a 176) a
177) b 178) c 179) d 180) b
181) a 182) b 183) d 184) b
185) b 186) b 187) a 188) a
189) a 190) a 191) c 192) d
193) c 194) c 195) d 196) c
197) d 198) a 199) b 200) a
NEET MCQs: Inheritance & Variation Page| 57 – ANSWER KEY – HINTS AND SOLUTIONS :
1 (b)
Haemophilia is a recessive X-linked disease. A
female with defected single X-chromosome is
normal but, carrier of disease, and male with
defected single X-chromosome is haemophilic.
2 (a)
Genetic disorder may be grouped into two
categories
(i) Mendelian Disorders These genetic disorder
are mainly caused by alternation and mutation in
the single gene. They are transmitted to offsprings
following the principle of inheritance. Mendelian
disorder can be dominant or recessive. ๐.๐.,
haemophilia, colour blindness, sickle-cell
anaemia, cystic fibrosis, phenylketonuria,
thalassaemia.
(ii) Chromosomal Disorders Chromosomal
disorder are caused due to excess, absence, or
abnormal arrangement of one or more
chromosome, ๐.๐., Turnerโs syndrome, Downโs
syndrome, etc
3 (c)
The term gene was coined by Johanssen.
4 (a)
A dihybrid cross involves two pairs of contrasting
characters, e.g., yellow round seeded plant and
wrinkled. Green seedes plant(both pure lines)
homozygous. When a dihybrid cross is made
between two pure line of homolzygous parents,
then the ๐น1 generation shows hybrids with
dominant phenotypic effect. When ๐น1
heterozygous plants are self-ferilized to
produce๐น2 generation, four types of combinations
are obtained of which two are similar to parental
combination and other two are new
combinations. The phenotypic dihybrid ratio of
these four combinations in ๐น2 generation comes
out to be 9 : 3 : 3 : 1, while the genotypic dihybrid
ratio is 1 : 2 : 2 : 4 : 1 : 2: 1 : 2 : 1.
5 (c)
Chromosome is made up of DNA and histone
proteins.
6 (d)
Baldness is not a sex-limited trait. Balaness is a
sex influenced trait.
Linkage is an exception to the principle of
independent assortment in heredity.
Galactosemia is a hereditary disease that is
caused by the lack of a liver enzyme required to
digest galactose.
Small population size results in random genetic
drift in population.
7 (a)
The ๐น1 offsprings of pure tall and pure dwarf are
heterozygoous tall, which on selfing produces 1 :
1 ratio of breeding tall to breeding dwarf.
8 (b)
Exposure of โXโ rays enhance the frequency of
crossing over
9 (a)
The genotype of trihybrid would be AaBbCc. Eight
different types of gametes ABC, ABc, AbC, Abc,
aBC, aBc, abC, abc would be formed. The number
of zygotes would be 82=64.
10 (b)
Page| 60
The genetic composition of an organism, i.e., the
combination of all alleles possessed by an
organism is called genotype
11 (d)
In polyploidy there are more than one set of
chromosomes is presenโt in an organisms. It only
happens when cytokinesis doesnโt take place in
proper way
12 (a)
12
A dihybrid cross in pea
plant between yellow round (smooth) seeded and green wrinkled seeded plant. The cross proves the
principle of independent assortment
13 (d)
When the F1-hybrid (Rr Yy) of a dihybrid cross is
test crossed (crossed with double recessive
parent rryy), the F2-offspring appear in the
phenotypic and genotypic ratio of 1 : 1 : 1 : 1
confirming that F1-offspring was heterozygous in
both the traits. It is a cross between RrYyรrryy.
14 (c)
Allelomorphs or simply called allele represents a
pair of contrasting characters
15 (a)
Harmful mutation does not get elimated from the
gene pool because most of the harmful mutations
are recessive and they carried by heterozygous
condition in the individual. If they (mutation) are
dominant then they easily get eliminated by the
death of an organism
16 (a)
A-Common, B-Rare
17 (c)
Mendel died in 1884 long before his work came to
recognized. It was in 1900 when three worker
independently rediscovered the principles of
heredity already worked out by Mendel.
They were Hugo de Vries of Holland, Carl Correns
of Germany and Eric Tiron and Tschermark of
Austria
18 (a)
In gynandromorphs, some cells of body contain
XX and some cells XY genotype.
19 (d)
Post Mendelian Discoveries
Gene interaction is the influence of alleles and
nonalleles ion the normal phenotypic expression
of genes. It is two types, intragenic (allelic) and
intergenic (nonallelic). In the intragenic
interaction the two allels (present on the same
gene locus on the two homologous chromosome)
of a gene interact in such a way as to produce a
phenotypic expression different from typical
dominant-recessive phenotype, ๐.๐., incomplete
dominance, codominance, multiple alleles.
In intergenic or non-allelic interaction, two or
more independent gene present on the same or
different chromosomes interact to produce
different expression, ๐.๐., epistasis, duplicate
genes, complementary genes, supplementary
genes, lethal genes, inhibitory genes, etc.
20 (c)
Page| 61
Intermediate inheritance is incomplete
dominance in which dominant factor of a
heterozygote does not completely mask the
expression of recessive allele. In incomplete
dominance, genotypic and phenotypic ratio
remain the same and is 1 : 2 : 1.
21 (c)
Green pod colour is dominant.
7 dominant traits, 7 recessive traits total 14 traits
or 7 oppossing pairs of traits
Characters Dominant
Traits
Recessive
Traits
Seed shape
Seed colour
Flower
colour
Pod shape
Pod colour
Flower
position
Stem
height
Round
Yellow
Violet
Full
Green
Axial
Tail
Wrinkled
Green
White
Constricted
Yellow
Terminal
Dwarf
22 (a)
IA IB are the dominant form of I gene, I is
recessive form
23 (a)
A-statistical analysis; B-mathematical logic
24 (d)
ZW and ZZ and ZOZZ.
ZW and ZZ Type of Sex Determination This
mechanism operates in certain insects (butterflies
and moths) and in vertebrates (fishes, reptiles
and birds). The male has two homomorphic sex
chromosomes (ZZ) and is homogametic and the
female has two heteromorphic sex chromosomes
(ZW) and is heterogametic. There are thus two
types of eggs with Z and with W and only one type
of sperms. i.e., each with Z
WZ-ZZ types of sex determination
25 (a)
If a character is expressed equally in the
homozygous and heterozygous conditions, it is
called dominant and the other character is said to
be recessive. In given question, โTallโ character is
dominant over โdwarfโ, hence, the cross shows
dominance and segregation of traits.
26 (b)
The best method to determine homozygosity and heterozygosity of an individual is back cross.
Crossing of F1 (dominant phenotype) to any one of the parent called back cross and when phenotype of
crossing parent is recessive than this is called test cross. The progeny of such cross can easily be analysed
to predict the genotype of test organism
27 (c)
Presence of one Barr body indicates the person
under investigation is a normal female.
28 (a)
A-Male, B-Female, C-Gametes.
XY and XY type sex determination seen in many
insect and mammals including humans. Males
have X and Y chromosome along with autosome
and females have pair of โXโ chromosome along
with autosome
Parents Phenotypes Male
Female
Page| 62
Genotypes 44A + XY
44A + XX
Gametes 22A + X 22A+Y
22A + A22A + X
22A+ X 22A+X
Children 22A + X 44A + XX 44 A + XY
Female
22A + Y 44 A + XY 44 A + XY
Male
Sex ratio Female : Male = 1 : 1
In plants The flowering plants are mostly bisexual
and lack sex chromosomes. The unisexual
flowering plants tent to have XX-XY type of sex
chromosomal mechanism for sex determination.
The female plants are XX and male plants are XY.
XX and XO Type of Sex Determination
Found in insect like grasshopper, cockroaches and
bugs. Males have only X sex-chromosome and
autosomes, female have pair of X-chromosome
and autosome
Parents Phenotypes Male Female
Genotypes ๐ด๐ด+๐๐ ๐ด๐ด+๐๐
Gametes ๐ด+๐,๐ด+๐ ๐ด+๐,๐ด+๐
๏ฟฝ
๏ฟฝ๐-generation
XX-XO type of sex determination
29 (c)
Female is sterile.
Disorders Autosomal/Sex
Linked
Symptoms Effects
Downโs
syndrome
Autosomal
aneuploidy
(trisomy, +21)
Mongolian eyefold
(epicanthus), open
mouth, protruded
tongue, projected
lower lip, many
loops on finger tip,
palm crease
Retarded
mental
development
IQ (below 40)
Turnerโs
syndrome
Sex
chromosomal
monosomy 44
- XO
Short stature
females (<5โ),
webbed neck, body
hair absent
menstrual cycle
absent. Sparse
pubic hair,
underdeveloped
breasts narrow lips
puffy fingers
Sterile
hearing
problem
Klinefelterโs
syndrome
Sex
chromosomal
aneuploidy
(tri/tetrasomy
of X
chromosome)
44+XXY
44+XXXY
The males are tall
with long legs,
testes small, sparse
body hair, Barr
body present,
breast enlargement
Gynaecomast
ia azospermia
sterile
Some Examples of Aneuploidy
(i) Downโs syndrome-21 trisomy
Symptoms
(a) Short statured with small round head
(b) Partially open mouth with protruding furrowed tongue
(c) Palm is broad with characteristic palm crease
(d) Slow mental development
(ii) Turnerโs syndrome
Page| 63
Cause Absence of one of the X-chromosomes, resulting in the karyotype 44+XO
Symptoms
(a) Sterile female with rudimentary ovaries
(b) Shield-shaped thorax
(c) Webbed neck
(d) Poor development of breasts
(e) Short stature, small uterus, puffy fingers
(iii) Klinefelterโs syndrome
Cause Presence of an additional copy of X-chromosome resulting in the karyotype 44+XXY
Symptoms
(a) Sex of the individual is masculine but possess feminine characters
(b) Gynaecomastia, i.e., development of breasts
(c) Poor beard growth and often sterile
(d) Feminine pitched voice
30 (c)
The environmental stress (as pesticides) does not
cause the direct changes in genome, instead, it
simply selects rather persisting mutations, which
result in phenotypes that are better adapted to
the new environment (e.g., certain pesticides).
31 (c)
A Lampbrush chromosomes is made up of two
homologous chromosomes held at several places
by chiasmata. The chromosomes are found in
oocytes of many invertebrates and all vertebrates
except some mammals. Lampbrush chromosomes
are found during the extended diplotene phase of
first meiotic division.
32 (c)
A gene consists of a polynucleotide sequence that
encodes a functional polypeptide or RNA
sequence.
33 (a)
XY and XY type sex determination seen in many
insect and mammals including humans. Males
have X and Y chromosome along with autosome
and females have pair of โXโ chromosome along
with autosome
Parents Phenotypes Male
Female
Genotypes 44A + XY
44A + XX
Gametes 22A + X 22A+Y
22A + A22A + X
22A+ X 22A+X
Children 22A + X 44A + XX 44 A + XY
Female
22A + Y 44 A + XY 44 A + XY
Male
Sex ratio Female : Male = 1 : 1
In plants The flowering plants are mostly bisexual
and lack sex chromosomes. The unisexual
flowering plants tent to have XX-XY type of sex
chromosomal mechanism for sex determination.
The female plants are XX and male plants are XY.
XX and XO Type of Sex Determination
Found in insect like grasshopper, cockroaches and
bugs. Males have only X sex-chromosome and
autosomes, female have pair of X-chromosome
and autosome
Parents Phenotypes Male Female
Genotypes ๐ด๐ด+๐๐ ๐ด๐ด+๐๐
Gametes ๐ด+๐,๐ด+๐ ๐ด+๐,๐ด+๐
๏ฟฝ
๏ฟฝ๐-generation
XX-XO type of sex determination
34 (c)
Frameshift mutations are the mutations caused by
insertion (i.e., addition) or deletion of one or
more nitrogen bases in the DNA or RNA. This type
of mutation alters the nucleotide sequences in all
the genes and hence, the genetic code is changed
totally, fro the point of mutation which results in
the change in biochemical behaviour of the genes.
Base pair substitution mutations involve
substitution of a aitrogen base by another base or
by some derivative of nitrogen base.
35 (c)
Page| 64
According to law of segregation, the heredity
character in the form of alleles segregate from
each other during gamete formation, i.e, each
gamete carry only one allele of each gene. This is
also called law of purity of gametes. When tall and
dwarf plants are crossed only tall plants are
produced in ๐น1 generation. By selfing of these ๐น1
plants tall and dwarf plants produced in 3 : 1
ratio.
36 (b)
Mendelโs law are able to predict accurately the
pattern of inheritance for a situation in which
alleles shows the complete dominance. Effect of
environment, other alleles did not explained by
the Mendel. Mendel did not know about the
polygenic traits also
37 (b)
Blood group-O has no antigens but A and B
antibodies.
38 (d)
Colour blindness disease was detected by Wilson
in 1910.
39 (a)
In the dihybrid cross between RRYY and rryy
parents, the number of RrYy genotypes in ๐น2
generation will be four.
40 (d)
Allelism refers to presence of alternative forms of
a gene at a given locus. Alleles or allelomorphs are
the two contrasting aspects of the same character
present at a locus of homologous pair of
chromosomes. Now โa-days, the same aspect in
duplicate (TT or tt) of a character is also
considered an allele.
41 (d)
The women with albinic father has gene for
albinism. When this women marries with albinic
men, they produce normal and albinic in 1 : 1
ratio.
42 (a)
ZO and ZZ type of sex determination. This
mechanism occurs in certain buttterfiles and
moths. The female is heterogametic and produces
two types of eggs half with Z and half without Z
chromosome. The males have homomorphic sex
chromosomes and is homogametic. It forms only
one kind of sperms, each with Z-chromosome
Parents Phenotypes Male Female
Genotypes AA + ZZ AA +ZO
Gametes A+Z, A+Z A +Z, A+O
๏ฟฝ
๏ฟฝ๐-generation
ZO-ZZ type of sex determination
43 (c)
Mendelโs law of independent assortment states
that,โthe alleles of different genes segregate
independently of each other during meiosisโ.
44 (a)
XX and XO chromosome.
XY and XY type sex determination seen in many
insect and mammals including humans. Males
have X and Y chromosome along with autosome
and females have pair of โXโ chromosome along
with autosome
Parents Phenotypes Male
Female
Genotypes 44A + XY
44A + XX
Gametes 22A + X 22A+Y
22A + A22A + X
22A+ X 22A+X
Children 22A + X 44A + XX 44 A + XY
Female
22A + Y 44 A + XY 44 A + XY
Male
Sex ratio Female : Male = 1 : 1
In plants The flowering plants are mostly bisexual
and lack sex chromosomes. The unisexual
flowering plants tent to have XX-XY type of sex
chromosomal mechanism for sex determination.
The female plants are XX and male plants are XY.
XX and XO Type of Sex Determination
Found in insect like grasshopper, cockroaches and
bugs. Males have only X sex-chromosome and
autosomes, female have pair of X-chromosome
and autosome
Parents Phenotypes Male Female
Genotypes ๐ด๐ด+๐๐ ๐ด๐ด+๐๐
Gametes ๐ด+๐,๐ด+๐ ๐ด+๐,๐ด+๐
๏ฟฝ
๏ฟฝ๐-generation
Page| 65
XX-XO type of sex determination
45 (b)
A-Chromatid, B-Allele pair, C-Genetic composition
46 (b)
The position of centromere determines the shape
of chromosome.
47 (b)
After schooling Mendel joined Augustinian
monastery of St. Thomas at Brunn (then in
Austria now Brunn in Czechoslovakia) in 1843 at
the age of 21. At the age of 25 (1847), he was
made a prist in that monastery
48 (a)
It was TH Morgan who clearly proved and define
linkage on the basis of the breeding experiments
in fruitfly. In 1911, Morgan and Castle proposed
โchromosomalโ theory of linkageโ
49 (d)
Francis Galton(1885) gave the term eugenics.
Eugenics is the improvement of human race by
the application of principles of genetics. The other
meaning of eugenics is โscience of being well
bornโ.
50 (c)
The test cross involves the crossing of F1hybrid
with a double recessive genotypic parent. By test
cross, the heterozygocity and homozygocity of the
organism can be tested.
51 (a)
Tetraploid endosperm is obtained, when a diploid
female and tetraploid male plants are crossed.
52 (a)
Colour Blindness
(i) It is a sex-linked recessive disorder
(ii) It results in defect in either red or and green
cone cells of eye resulting in failure to
discriminate between red and green colour
(iii) The gene for colour blindness is present on X
chromosome
(iv) It is observed more in males (XcY) because of
presence of only one X-chromosome as compared
to two chromosomes in famales
53 (a)
When the ๐น1-hybrid is crossed with recessive
parent, both phenotypes appear in progeny and
this is called test cross. It gives 1 : 1 ratio in
monohybrid cross and 1 : 1 : 1 : 1 ratio in dihybrid
cross.
54 (d)
Thus, the genotype of parents will be BOรAO.
55 (b)
Symbol in pedigree chart represents still death
56 (c)
Histones are basic proteins found in the
eukaryotic chromosomes. These are rich in basic
amino acids lysine and arginine. There are
basically five types of histones, i.e.,
H1,H2A,H2B,H3 and H4 which have been studied
in almost all eukaryotic cells.
57 (a)
In monosomic condition, one chromosome is
missing from the somatic chromosome
complement. It is denoted by 2n-1. When somatic
cells of an organism contain three copies of one
chromosome, the condition is known as trisomy.
It is denoted by 2n+1. Therefore, monosomic
trisomy is represented as 2n-1+1.
58 (a)
Baldness is common in humans. Hereditary
baldness is carried by a dominant autosomal
gene. It develops only in men and never in
women.
59 (a)
Thalassaemia
(i) It is an autosome-linked recessive disesase
(ii) It occurs due to either mutation or deletion
resulting in reduced rate of synthesis of one of
globin chains of haemoglobin
(iii) Anaemia is the characteristic of this disease
(iv) Thalassaemia is classified into two types
- ๐-thalassaemia Production of ฮฑ-globin
chain is affected. It is controlled by the
closely linked genes HBA1 and HBA2 on
Page| 66
chromosome 16. It occurs due to mutation
or deletion of one or more of the four
genes.
- ๐-thalassaemia Production of ฮฒ-globin
chain is affected. It occurs due to mutation
of one or both HBB genes on chromosome
11
60 (a)
The term โmutationโ was introduced by Hugo de
Vries in 1901 and his mutation theory of
evolution called mutation theory of evolution.
Mutation is new sudden inheritable change in
organism due to permanent change in their
genotype
61 (d)
Because in sex linked inheritance the chance of
girl or female to be affected is almost nill.
Generally, the females are carriers and in
heterozygous condition
62 (b)
Non-disjunction is the condition in which the
separation of chromosome doesnโt take place
during cell division. In 44+XY non-disjunction
there is non-separation of XY gene is there, which
leads to the formation of sperm having genotypes,
22+XY and 22
63 (c)
Linkage prevents independent assortment.
64 (d)
Sex influenced trait.
Finalization of sex at the time of fertilization is
known as sex determination. All sex linked
character show criss-cross inheritance and firstly
it was studied and discovered by TH Morgan
(1910). Sex related trait may be divided into three
types
(i) Sex Linked Traits They are those traits the
determining genes of which are found on the sex
chromosomes. All the sex-linked traits present on
a sex chromosome are inherited together
(ii) Sex Limited Traits They are autosomal traits
which are expressed in a particular sex in
response to sex hormones although their genes
also occur in the other sex, e.g., milk secretion in
mammalian females, pattern baldness in males.
The gene for baldness behaves as an autosomal
dominant in males and autosomal recessive in
females
(iii) Sex Influenced Traits The traits are not due to
particular genes but are by products of sex
hormones, e.g., low pitched voice, beard
moustaches. In males, pattern baldness is related
to both autosomal genes as well as excessive
secretion of testosterone
65 (c)
Since in an individual only two alleles can be
present, multiple alleles can be found only when
population studies are made
66 (c)
Biological concept of species says that only the
members of a species can breed freely in nature to
produce fertile offsprings. The plant tobacco
(๐๐๐๐๐ก๐๐๐๐) has two different species,
๏ฟฝ
๏ฟฝ๐๐๐๐ก๐๐๐๐ ๐ก๐๐๐๐๐๐ข๐ and ๐๐๐๐๐ก๐๐๐๐ ๐ ๐ฆ๐๐ฃ๐๐ ๐ก๐๐๐ .
These two species cannot reproduce freely.
67 (b)
In duplication there is increase in size of genes by
duplication of it segment of a chromosome.
Mainly seen in case of plants. But in deletion there
is loss of genes or segment of chromosome
68 (d)
The types of gametes produced by a plant depend
upon the number of hetrozygous pair.
Number of types of gametes=2๐
N=Number of heterozygous pair
21=2
The gametes are-ABC and AbC.
69 (c)
In trisomic condition, diploid organism have extra
chromosome represented by the chromosomal
formula2๐+1 . One of the pairs of chromosomes
has an extra member, so that a trivalent may be
formed during meiotic prophase, e.g., Downโs
syndrome (45+XX or 45+XY), Klinefelterโs
syndrome (44 + XXY).
In monosomic, diploid organism has one
chromosome of a single pair missing with
genomic formula 2๐โ1. Monosomics can from
two kind of gametes, (n) and (n-1),
e.g., Turnerโs syndrome (44 + X).
70 (d)
Page| 67
When a normal man marries a normal woman,
whose father was colourblind then their 50%
sons are colourblind (50% sons normal) and all
the daughters are phenotypically normal(carrier
woman also are phenotypically normal).
The female parent is carrier as it receives a
defective X-chromosome from her father.
71 (c)
Testosterone in male secreted by Leydig cells. In
the male testosterone is essential for
development of secondary sexual character and
related to baldness also
72 (d)
The disorder cystic fibrosis, sickle cell anaemia,
colour blindness and haemophilia are caused due
to the abnormality in gene (Mendelian factor).
Turnerโs syndrome is due to chromosomal
abnormality. It is characterized by 44 autosomes
and only one X-chromosome.
73 (d)
Haemophilia is a X-linked disorder not Y-linked.
74 (c)
(Homozygous tall) ร (Homozygous dwarf)
Phenotypic ratio 1 : 1 (50% tall, 50% dwarf)
Genotypic ratio 1 : 1
75 (c)
ฮณโrays generally induce mutations.
76 (d)
Since genotypes/phenotypes of both parents are
same but only sources of gametes are reversed,
these crosses are called reciprocal crosses.
77 (a)
Man has only one X-chromosome that is inherited
to his daughter. Therefore, a hereditary disease,
which is X-chromosomal linked, is never passed
on from father to son.
78 (a)
Bateson gave the coupling and repulsion
hypothesis for linkage and crossing over.
Similar genes remain together they donโt go for
crossing over. Bateson called them coupling
gones.
While on the other hand dissimilar gene segregate
crossing over takes place. Bateson called them
repulsion parents gene
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