Getting ready for your Class 7 Science PA1 Class Test Exam Paper 2025 ? You’ve come to the right spot! This page offers a comprehensive Class 7 Science PA1 Class Test Exam Paper 2025, along with a detailed marking scheme to guide you in structuring your answers and maximizing your score.

The paper is crafted in line with the most recent CBSE guidelines, ensuring it covers all key chapters and concepts from the PA1 syllabus. With a well-defined question format and step-by-step marking, this resource is designed to help you practice effectively, manage your time during the exam, and boost your overall performance.
Download Class 7 Science PA1 Class Test Exam Paper 2025 With Marking Scheme – PDF Format
Are you looking for the Class 7 Science PA1 Class Test Exam Paper 2025 along with a detailed marking scheme? We’ve got you covered! This PDF includes all important questions as per the latest syllabus, helping students prepare effectively for their exams. Click the button below to download the paper and start your smart preparation today!
PA1 EXAMINATION
Subject: SCIENCE
Class: VII
Marks: 40
Time: 1.5 Hours
The question paper is divided into three sections:
- Detailed Assessment – 10 marks
- Descriptive/Subjective Type Questions – 30 marks
General Instructions:
- i. This question paper consists of 11 questions divided into 3 sections.
- ii. All questions are compulsory. However, an internal choice is provided in some questions. A student is expected to attempt only one of these questions.
- iii. Section A consists of 5 questions, each carrying 2 marks.
- iv. Section B consists of 4 questions, each carrying 3 marks. Answers should be in the range of 30 to 50 words.
- v. Section C consists of 2 long-answer type questions, each carrying 4 marks. Answers should be in the range of 50 to 80 words.
SECTION A
(Each question carries 2 marks)
- How can we determine whether an image formed by a mirror or a lens is real or virtual?
- Here are a few words and numbers. Write down how they will appear in a plane mirror:
a. AMBULANCE
b. LEFT
c. 12345678
d. 8888 - Differentiate between regular and irregular reflection.
- Write the chemical symbols/formulas for the following:
i. Sulphur
ii. Phosphorus
iii. Hydrochloric acid
iv. Zinc oxide OR
Name all the elements present in the following compounds: - How does the diaphragm assist in the process of breathing (pumping air)?
SECTION B
(Each question carries 3 marks. Answers should be in the range of 30 to 50 words)
- Balance the following chemical equations:
a. H₂ + O₂ → H₂O
b. N₂ + H₂ → NH₃
c. KClO₃ → KCl + O₂
d. HCl + Mg(OH)₂ → MgCl₂ + H₂O
e. K + H₂O → KOH + H₂ - What are the different types of asexual reproduction? Explain any two of them.
- How can we determine whether an image formed by a mirror or a lens is real or virtual?
- Describe how gas exchange takes place in the human respiratory system. OR
What is the difference between aerobic and anaerobic respiration? Write the equations to show both processes.
SECTION C
(Each question carries 4 marks. Answers should be in the range of 50 to 80 words)
- Complete the following word equations and provide their balanced chemical equations:
a. Magnesium + oxygen → __
b. Iron + oxygen + water → __
c. Vinegar + baking soda → __
d. Carbon dioxide + lime water → __
e. Copper sulphate + iron → __
f. Carbon dioxide + limestone → __ - Name the various agents of pollination. Also, provide one example of a flower pollinated by each agent.
OR
Describe the various steps involved in tissue culture.
Class 7 Science PA1 Class Test Exam Paper 2025 – Marking Scheme
SECTION A
(Each question carries 2 marks)
- How can we determine whether an image formed by a mirror or a lens is real or virtual?
- Answer:
- Try to capture it on a screen:
- Real image: Can be formed on a screen.
- Virtual image: Cannot be projected on a screen.
- You can also check the orientation:
- Real images are usually inverted.
- Virtual images are upright.
- Marking:
- 1 mark for stating the difference between real and virtual images.
- 1 mark for providing the criteria for determining the nature of the image.
- Try to capture it on a screen:
- 2. How will the following words/numbers appear in a plane mirror?
a. AMBULANCE
b. LEFT
c. 12345678
d. 8888- Answer:
- AMBULANCE: Will appear reversed as ECNALUBMA.
- LEFT: Will appear reversed as TFEL.
- 12345678: Will appear reversed as 87654321.
- 8888: Will appear the same as 8888.
- Marking:
- ½ mark for each correct answer (total of 2 marks).
- Answer:
- 3. Differentiate between regular and irregular reflection.
- Answer:
- Regular Reflection: Occurs on smooth surfaces (e.g., plane mirror), producing a clear image.
- Irregular Reflection: Occurs on rough surfaces, scattering light in all directions, resulting in no clear image.
- Marking:
- 1 mark for defining regular reflection.
- 1 mark for defining irregular reflection.
- Answer:
- 4. Write the chemical symbols/formulas for the following:
i. Sulphur = S
ii. Phosphorus = P
iii. Hydrochloric acid = HCl
iv. Zinc oxide = ZnO - OR
- Name the elements present in the following compounds:
- SO₂ = Sulphur (S), Oxygen (O)
- PbCl₂ = Lead (Pb), Chlorine (Cl)
- Ba(OH)₂ = Barium (Ba), Oxygen (O), Hydrogen (H)
- LiF = Lithium (Li), Fluorine (F)
- Marking:
- ½ mark for each correct formula or element (total of 2 marks).
- How does the diaphragm assist in the process of breathing (pumping air)?
- Answer:
- The diaphragm contracts and moves downward to increase the chest volume, causing air to be drawn in during inhalation. It relaxes and moves upward during exhalation to push air out of the lungs.
- Marking:
- 1 mark for describing the role of the diaphragm in inhalation.
- 1 mark for describing the role of the diaphragm in exhalation.
- Answer:
SECTION B
(Each question carries 3 marks. Answers should be in the range of 30 to 50 words)
- Balance the following chemical equations:
a. H₂ + O₂ → H₂O → 2H₂ + O₂ → 2H₂O
b. N₂ + H₂ → NH₃ → N₂ + 3H₂ → 2NH₃
c. KClO₃ → KCl + O₂ → 2KClO₃ → 2KCl + 3O₂
d. HCl + Mg(OH)₂ → MgCl₂ + H₂O → 2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
e. K + H₂O → KOH + H₂ → 2K + 2H₂O → 2KOH + H₂- Marking:
- ½ mark for each correct equation (total of 3 marks).
- Marking:
- What are the different types of asexual reproduction? Explain any two of them.
- Answer:
- Types of Asexual Reproduction:
- Binary Fission (e.g., in Amoeba): One organism divides into two identical parts.
- Budding (e.g., in Hydra): A new organism grows out of the parent organism.
- Vegetative Propagation (e.g., in plants): New plants are produced from the roots, stems, or leaves of the parent plant.
- Types of Asexual Reproduction:
- Marking:
- 1 mark for listing different types.
- 2 marks for explaining any two types with examples.
- Answer:
- How can we determine whether an image formed by a mirror or a lens is real or virtual?
- Answer:
- A real image is formed when light rays converge, and it can be projected onto a screen. A virtual image is formed when light rays appear to diverge but do not actually converge.
- Marking:
- 1 mark for explaining the difference between real and virtual images.
- 2 marks for providing a method to determine the nature of the image.
- Answer:
- Describe how gas exchange takes place in the human respiratory system.
- Answer:
- Gas exchange occurs in the alveoli, where oxygen from the air is transferred to the blood, and carbon dioxide from the blood is expelled into the air to be exhaled. This process happens due to the difference in concentration of gases on either side of the alveolar membrane.
- Marking:
- 1 mark for describing the location of gas exchange.
- 2 marks for explaining the process of oxygen and carbon dioxide exchange.
What is the difference between aerobic and anaerobic respiration? Write the equations to show both processes.- Answer:
- Aerobic Respiration: Takes place in the presence of oxygen. Glucose is broken down to release energy.
- Equation: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy
- Anaerobic Respiration: Takes place in the absence of oxygen. Glucose is broken down to release energy.
- Equation (in muscles): C₆H₁₂O₆ → 2C₃H₆O₃ + Energy
- Aerobic Respiration: Takes place in the presence of oxygen. Glucose is broken down to release energy.
- Marking:
- 1 mark for defining aerobic and anaerobic respiration.
- 2 marks for writing the correct equations.
- Answer:
SECTION C
(Each question carries 4 marks. Answers should be in the range of 50 to 80 words)
- Complete the following word equations and provide their balanced chemical equations:
- a. Magnesium + oxygen → Magnesium oxide
- Balanced Equation: 2Mg + O₂ → 2MgO
b. Iron + oxygen + water → Iron(III) oxide - Balanced Equation: 3Fe + 4O₂ + 6H₂O → 2Fe₂O₃·3H₂O
c. Vinegar + baking soda → Carbon dioxide + water + sodium acetate - Balanced Equation: CH₃COOH + NaHCO₃ → CO₂ + H₂O + NaCH₃COO
d. Carbon dioxide + lime water → Calcium carbonate - Balanced Equation: CO₂ + Ca(OH)₂ → CaCO₃ + H₂O
e. Copper sulphate + iron → Iron(II) sulphate + copper - Balanced Equation: CuSO₄ + Fe → FeSO₄ + Cu
f. Carbon dioxide + limestone → Calcium carbonate - Balanced Equation: CO₂ + CaCO₃ → CaCO₃
- Marking:
- ½ mark for each word equation.
- ½ mark for each correct balanced chemical equation (total of 4 marks).
- Name the various agents of pollination. Also, provide one example of a flower pollinated by each agent.
- Answer:
- Agents of Pollination:
- Wind Pollination (e.g., Maize)
- Water Pollination (e.g., Water lily)
- Insect Pollination (e.g., Rose)
- Bird Pollination (e.g., Hibiscus)
- Agents of Pollination:
- Marking:
- 2 marks for naming the agents.
- 2 marks for providing examples of flowers pollinated by each agent.
OR
Describe the various steps involved in tissue culture.
- Answer:
- Steps in Tissue Culture:
- Selection of plant tissue.
- Sterilization of the tissue to prevent contamination.
- Placing the tissue in a sterile culture medium containing nutrients and hormones.
- Formation of a callus (undifferentiated cells).
- Inducing differentiation to form shoots and roots.
- Transplanting the plantlets into soil.
- Steps in Tissue Culture:
Class-wise Solutions
Class 12:
Class 12 Physics – NCERT Solutions
Class 12 Chemistry – NCERT Solutions
Class 11:
- Class 11 Physics – NCERT Solutions
- Class 11 Chemistry – NCERT Solutions
- Class 11 Biology – NCERT Solutions
- Class 11 Math – NCERT Solutions
Class 10:
Class 9:
Class 8:
Class 7:
Class 6:
Subject-wise Solutions
Physics:
Chemistry:
Biology:
Math:
- Class 11 Math – NCERT Solutions
- Class 10 Math – NCERT Solutions
- Class 9 Math – NCERT Solutions
- Class 8 Math – NCERT Solutions
Science:
- Class 10 Science – NCERT Solutions
- Class 9 Science – NCERT Solutions
- Class 8 Science – Oxford Solutions
- Class 7 Science – Oxford Solutions
- Class 6 Science – Oxford Solutions
NEET BIOLOGY
- Evolution
- Breathing and Exchange of Gases
- Anatomy of Flowering Plants
- Body Fluids and Circulation
- Human Health and Disease
- Microbes in Human Welfare
- Cell Cycle and Cell Division
- Biotechnology and Its Applications
- Biodiversity and Conservation
- Morphology of Flowering Plants
For the official Class 7 Mathematics Solutions, you can visit:
- NCERT Textbooks (for Class 7):