Class 9 Math Ch 3 Coordinate Geometry Ex 3.2 is the bridge between algebra and geometry. It allows us to represent geometric figures using algebraic equations and understand their positions using coordinates on a graph.
In Exercise 3.2, you’ll work with the Cartesian plane and learn how to:
- Identify and plot points accurately on the graph.
- Understand the position of points in all four quadrants.
- Interpret and draw conclusions from given coordinates.
This exercise builds your confidence in visualizing algebraic points and prepares you for more advanced topics involving graphs and equations.
Key Concepts Covered in Ex 3.2:
- The x-axis and y-axis divide the plane into four quadrants.
- The signs of coordinates change depending on the quadrant:
- I Quadrant: (+x, +y)
- II Quadrant: (–x, +y)
- III Quadrant: (–x, –y)
- IV Quadrant: (+x, –y)
- Plotting of points like A(2, 3), B(–4, –2), etc., on the graph.
By solving this exercise, you’ll gain accuracy and a strong conceptual understanding of how to work with coordinate points.
Class 9 Math Ch 3 Coordinate Geometry Ex 3.2
Ex 3.2 Class 9 Maths
Question 1
Write the answer of each of the following questions:
(i) What is the name of horizontal and the vertical lines drawn to determine the position of any point in the Cartesian plane?
(ii) What is the name of each part of the plane formed by these two lines?
(iii) Write the name of the point where these two lines intersect.
Solution:
(i) The horizontal line: x – axis and the vertical line: y – axis.
(ii) Each part is called “Quadrant”.
(iii) Origin
Ex 3.2 Class 9 Maths Question 2
See the given figure and write the following:
(i) The coordinates of B.
(ii) The coordinates of C.
(iii) The point identified by the coordinates (-3,-5).
(iv) The point identified by the coordinates (2,-4).
(v) The abscissa of the point D.
(vi) The ordinate of the point H.
(vii) The coordinates of the point L.
(viii) The coordinates of the point M.
Solution:
From the figure, we have
(i) The coordinates of B are (-5,2).
(ii) The coordinates of C are (5, -5).
(iii) The point E is identified by the coordinates (-3,-5).
(iv) The point G is identified by the coordinates (2,-4).
(v) The abscissa of the point D is 6.
(vi) The ordinate of the point H is -3.
(vii) The coordinates of the point L are (0,5). (viii) The coordinates of the point M are (-3,0).
NCERT Solutions for Class 9 Maths Chapter 3 Coordinate Geometry Ex 3.3
Ex 3.3 Class 9 Maths Question 1
In which quadrant or on which axis do each of the points (-2, 4),(3, -1), (-1, 0),(1, 2) and (-3, -5) lie? Verify your answer by locating them on the Cartesian plane.
Solution:
The point (-2, 4) is having negative abscissa and positive ordinate.
∴ (-2,4) lies in the 2nd quadrant.
The point (3, -1) is having positive abscissa and negative ordinate.
∴ (3, -1) lies in the 4th quadrant.
The point (-1, 0) is having negative abscissa and zero ordinate.
∴ The point (-1, 0) lies on the negative x-axis.
The point (1, 2) is having the abscissa as well as ordinate positive.
∴ Point (1,2) lies in the 1st quadrant.
The point (-3, -5) is having the abscissa as well as ordinate negative.
∴ Point (-3, -5) lies in the 3rd quadrant.
These points are plotted in the Cartesian plane as shown in the following figure as A(-2, 4); B(3, -1); C(-l, 0); D(l, 2) and E (-3, -5).
Ex 3.3 Class 9 Maths Question 2
Plot the points (x, y) given in the following table on the plane, choosing suitable units of distance on the axes.
Solution:
The given points are (-2, 8), (-1, 7), (0, -1.25), (1,3) and (3, -1).
To plot these points:
(i) We draw X’OX and YOY’ as axes.
(ii) We choose suitable units of distance on the axes.
(iii) To plot (-2,8), we start from O, take (-2) units on x-axis and then (+8) units on y – axis. We mark the point as A (-2, 8).
(iv) To plot (-1,7), we start from O, take (-1) units on x-axis and then (+7) units on the y – axis. We mark the point as B(-1, 7).
(v) To plot (0, -1.25), we move along 1.25 units below the x-axis on the y – axis and mark the point as C(0, -1.25).
(vi) To plot (1, 3), we take (+1) unit on the x-axis and then (+3) units on the y – axis. We mark the point as D(1, 3).
(vii) To plot (3, -1), we take (+3) units on the x-axis and then (-1) unit on the y – axis. We mark the point E(3, -1).
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