Class 8 Math Ch 2 Linear Equation Ex 2.1-NCERT Book

Class 8 Math Ch 2 Linear Equation Ex 2.1-NCERT Book

Class 8 Math Ch 2 Linear Equation Ex 2.1-NCERT Book

Ex 2.1 Class 8 Maths 

Question 1.
Solve the equation: x – 2 = 7
.
Solution:
Given: x – 2 = 7
β‡’ x – 2 + 2 = 7 + 2 (adding 2 on both sides)
β‡’ x = 9 (Required solution)

Ex 2.1 Class 8 Maths Question 2.
Solve the equation: y + 3 = 10.
Given: y + 3 = 10
β‡’ y + 3 – 3 = 10 – 3 (subtracting 3 from each side)
β‡’ y = 7 (Required solution)

Ex 2.1 Class 8 Maths Question 3.
Solve the equation: 6 = z + 2
Solution:
We have 6 = z + 2
β‡’ 6 – 2 = z + 2 – 2 (subtracting 2 from each side)
β‡’ 4 = z
Thus, z = 4 is the required solution.

Ex 2.1 Class 8 Maths Question 4.
Solve the equations: 37 + x = 177
Solution:
NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q4

Ex 2.1 Class 8 Maths Question 5.
Solve the equation 6x = 12.
Solution:
We have 6x = 12
β‡’ 6x Γ· 6 = 12 Γ· 6 (dividing each side by 6)
β‡’ x = 2
Thus, x = 2 is the required solution.

Ex 2.1 Class 8 Maths Question 6.
Solve the equation t5 = 10.
Solution:
Given t5 = 10
β‡’ t5 Γ— 5 = 10 Γ— 5 (multiplying both sides by 5)
β‡’ t = 50
Thus, t = 50 is the required solution.

Ex 2.1 Class 8 Maths Question 7.
Solve the equation 2×3 = 18.
Solution:
We have 2×3 = 18
β‡’ 2×3 Γ— 3 = 18 Γ— 3 (multiplying both sides by 3)
β‡’ 2x = 54
β‡’ 2x Γ· 2 = 54 Γ· 2 (dividing both sides by 2)
β‡’ x = 27
Thus, x = 27 is the required solution.

Ex 2.1 Class 8 Maths Question 8.
Solve the equation 1.6 = y1.5
Solution:
Given: 1.6 = y1.5
β‡’ 1.6 Γ— 1.5 = y1.5 Γ— 1.5 (multiplying both sides by 1.5)
β‡’ 2.40 = y
Thus, y = 2.40 is the required solution.

Ex 2.1 Class 8 Maths Question 9.
Solve the equation 7x – 9 = 16.
Solution:
We have 7x – 9 = 16
β‡’ 7x – 9 + 9 = 16 + 9 (adding 9 to both sides)
β‡’ 7x = 25
β‡’ 7x Γ· 7 = 25 Γ· 7 (dividing both sides by 7)
β‡’ x = 257
Thus, x = 257 is the required solution.

Ex 2.1 Class 8 Maths Question 10.
Solve the equation 14y – 8 = 13.
Solution:
We have 14y – 8 = 13
β‡’ 14y – 8 + 8 = 13 + 8 (adding 8 to both sides)
β‡’ 14y = 21
β‡’ 14y Γ· 14 = 21 Γ· 14 (dividing both sides by 14)
β‡’ y = 2114
β‡’ y = 32
Thus, y = 32 is the required solution.

Ex 2.1 Class 8 Maths Question 11.
Solve the equation 17 + 6p = 9.
Solution:
We have, 17 + 6p = 9
β‡’ 17 – 17 + 6p = 9 – 17 (subtracting 17 from both sides)
β‡’ 6p = -8
β‡’ 6p Γ· 6 = -8 Γ· 6 (dividing both sides by 6)
β‡’ p = βˆ’86
β‡’ p = βˆ’43
Thus, p = βˆ’43 is the required solution.

Ex 2.1 Class 8 Maths Question 12.
Solve the equation x3 + 1 = 715
Solution:
NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q12

NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1 Q12.1

Class 8 Math Ch 2 Linear Equation Ex 2.1-NCERT Book-Chapter-wise link below

Class 8 Math Ch 2 Linear Equation Ex 2.1-NCERT Book

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For the official Class 10 Mathematics Solutions, you can visit:

  1. NCERT Textbooks (for Class 10):
    https://ncert.nic.in/textbook.php?class=10