Class 8 Maths Exercise 9.4 Easy Solutions NCERT

Class 8 Maths Exercise 9.4 Easy Solutions NCERT focuses on dividing algebraic expressions. In this exercise, students learn how to divide polynomials by monomials and binomials using basic algebraic rules. The step-by-step NCERT solutions provided here simplify the division process and help students understand the concepts more easily. With these easy-to-follow explanations, students can build their skills in dividing algebraic expressions confidently.

Class 8 Maths Exercise 9.4 Easy Solutions NCERT

Ex 9.4 Class 8 Maths Question 1.
Multiply the binomials:
(i) (2x + 5) and (4x – 3)
(ii) (y – 8) and (3y – 4)
(iii) (2.5l – 0.5m) and (2.5l + 0.5m)
(iv) (a + 3b) and (x + 5)
(v) (2pq + 3q2) and (3pq – 2q2)
(vi) (34a2 + 3b2) and 4(a2 β€“ 23 b2)

Solution:
(i) (2x + 5) Γ— (4x – 3)
= 2x Γ— (4x – 3) + 5 Γ— (4x – 3)
= (2x Γ— 4x) – (3 Γ— 2x) + (5 Γ— 4x) – (5 Γ— 3)

NCERT Books
= 8x2 β€“ 6x + 20x – 15
= 8x2 + 14x – 15

(ii) (y – 8) Γ— (3y – 4)
= y Γ— (3y – 4) – 8 Γ— (3y – 4)
= (y Γ— 3y) – (y Γ— 4) – (8 Γ— 3y) + (-8 Γ— -4)
= 3y2 β€“ 4y – 24y + 32
= 3y2 β€“ 28y + 32

(iii) (2.5l – 0.5m) Γ— (2.5l + 0.5m)
= (2.5l Γ— 2.5l) + (2.5l Γ— 0.5m) – (0.5m Γ— 2.5l) – (0.5m Γ— 0.5m)
= 6.25l2 + 1.25ml – 1.25ml – 0.25m2
= 6.25l2 + 0 – 0.25m2
= 6.25l2 β€“ 0.25m2

(iv) (a + 3b) Γ— (x + 5)
= a Γ— (x + 5) + 36 Γ— (x + 5)
= (a Γ— x) + (a Γ— 5) + (36 Γ— x) + (36 Γ— 5)
= ax + 5a + 3bx + 15b

(v) (2pq + 3q2) Γ— (3pq – 2q2)
= 2pq Γ— (3pq – 2q2) + 3q2 (3pq – 2q2)
= (2pq Γ— 3pq) – (2pq Γ— 2q2) + (3q2 Γ— 3pq) – (3q2 Γ— 2q2)
= 6p2q2 β€“ 4pq3 + 9pq3 β€“ 6q4
= 6p2q2 + 5pq3 β€“ 6q4

NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 Q1

Ex 9.4 Class 8 Maths Question 2.
Find the product:
(i) (5 – 2x) (3 + x)
(ii) (x + 7y) (7x – y)
(iii) (a2 + b) (a + b2)
(iv) (p2 β€“ q2)(2p + q)
Solution:
(i) (5 – 2x) (3 + x)
= 5(3 + x) – 2x(3 + x)
= (5 Γ— 3) + (5 Γ— x) – (2x Γ— 3) – (2x Γ— x)
= 15 + 5x – 6x – 2x2

(ii) (x + 7y) (7x – y)
= x(7x – y) + 7y(7x – y)
= (x Γ— 7x) – (x Γ— y) + (7y Γ— 7x) – (7y Γ— y)
= 7x2 β€“ xy + 49xy – 7y2
= 7x2 + 48xy – 7y2

(iii) (a2 + b) (a + b2)
= a2 (a + b2) + b(a + b2)
= (a2 Γ— a) + (a2 Γ— b2) + (b Γ— a) + (b Γ— b2)
= a3 + a2b2 + ab + b3

(iv) (p2 β€“ q2)(2p + q)
= p2(2p + q) – q2(2p + q)
= (p2 Γ— 2p) + (p2 Γ— q) – (q2 Γ— 2p) – (q2 Γ— q)
= 2p3 + p2q – 2pq2 β€“ q3

Ex 9.4 Class 8 Maths Question 3.
Simplify:
(i) (x2 β€“ 5) (x + 5) + 25
(ii) (a2 + 5)(b3 + 3) + 5
(iii) (t + s2) (t2 β€“ s)
(iv) (a + b) (c – d) + (a – b) (c + d) + 2(ac + bd)
(v) (x + y) (2x + y) + (x + 2y) (x – y)
(vi) (x + y)(x2 β€“ xy + y2)
(vii) (1.5x – 4y)(1.5x + 4y + 3) – 4.5x + 12y
(viii) (a + b + c) (a + b – c)
Solution:
(i) (x2 β€“ 5) (x + 5) + 25
= x2(x + 5) + 5(x + 5) + 25
= x3 + 5x2 β€“ 5x – 25 + 25
= x3 + 5x2 β€“ 5x + 0
= x3 + 5x2 β€“ 5x

(ii) (a2 + 5)(b3 + 3) + 5
= a2(b3 + 3) + 5(b3 + 3) + 5
= a2b3 + 3a2 + 5b3 + 15 + 5
= a2b3 + 3a2 + 5b3 + 20

(iii) (t + s2) (t2 β€“ s)
= t(t2 β€“ s) + s2(t2 β€“ s)
= t3 β€“ st + s2t2 β€“ s3
= t3 + s2t2 β€“ st – s3

(iv) (a + b)(c – d) + (a – b) (c + d) + 2(ac + bd)
= a(c – d) + b(c – d) + a(c + d) – b(c + d) + 2ac + 2bd
= ac – ad + bc – bd + ac + ad – bc – bd + 2ac + 2bd
= ac + ac + 2ac + bc – bc – ad + ad – bd – bd + 2bd
= 4ac + 0 + 0 + 0
= 4ac

(v) (x + y) (2x + y) + (x + 2y) (x – y)
= x(2x + y) + y(2x + y) + x(x – y) + 2y(x – y)
= 2x2 + xy + 2xy + y2 + x2 β€“ xy + 2xy – 2y2
= 2x2 + x2 + xy + 2xy – xy + 2xy + y2 β€“ 2y2
= 3x2 + 4xy – y2

(vi) (x + y)(x2 β€“ xy + y2)
= x(x2 β€“ xy + y2) + y(x2 β€“ xy + y2)
= x3 β€“ x2y + x2y + xy2 β€“ xy2 + y3
= x3 β€“ 0 + 0 + y3
= x3 + y3

(vii) (1.5x – 4y)(1.5x + 4y + 3) – 4.5x.+ 12y
= 1.5x (1.5x + 4y + 3) – 4y(1.5x + 4y + 3) – 4.5x + 12y
= 2.25x2 + 6xy + 4.5x – 6xy – 16y2 β€“ 12y – 4.5x + 12y
= 2.25x2 + 6xy – 6xy + 4.5x – 4.5x + 12y – 12y – 16y2
= 2.25x2 + 0 + 0 + 0 – 16y2
= 2.25x2 β€“ 16y2

(viii) (a + b + c) (a + b – c)
= a(a + b – c) + b(a + b – c) + c(a + b – c)
= a2 + ab – ac + ab + b2 β€“ bc + ac + bc – c2
= a2 + ab + ab – bc + bc – ac + ac + b2 β€“ c2
= a2 + 2ab + b2 β€“ c2 + 0 + 0
= a2 + 2ab + b2 β€“ c2

NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 q-1
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 q-1.1
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 q-2
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 q-3
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.4 q-3.1

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