Class 8 Maths Exercise 2.3 Easy Solutions NCERT deals with solving linear equations where the variable appears on both sides of the equation. This is an important skill that strengthens a studentβs ability to isolate variables and balance equations correctly. The problems in this exercise help develop logical thinking and algebraic manipulation.
These step-by-step NCERT solutions are designed to help students understand each concept clearly and improve their confidence in solving such equations.
Class 8 Maths Exercise 2.3 Easy Solutions NCERT
Solve the following equations and check your results.
Ex 2.3 Class 8 Maths Question 1.
3x = 2x + 18
Solution:
We have 3x = 2x + 18
β 3x β 2x = 18 (Transposing 2x to LHS)
β x = 18
Hence, x = 18 is the required solution.
Check: 3x = 2x + 18
Putting x = 18, we have
LHS = 3 Γ 18 = 54
RHS = 2 Γ 18 + 18 = 36 + 18 = 54
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 2.
5t β 3 = 3t β 5
Solution:
We have 5t β 3 = 3t β 5
β 5t β 3t β 3 = -5 (Transposing 3t to LHS)
β 2t = -5 + 3 (Transposing -3 to RHS)
β 2t = -2
β t = -2 Γ· 2
β t = -1
Hence t = -1 is the required solution.
Check: 5t β 3 = 3t β 5
Putting t = -1, we have
LHS = 5t β 3 = 5 Γ (-1)-3 = -5 β 3 = -8
RHS = 3t β 5 = 3 Γ (-1) β 5 = -3 β 5 = -8
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 3.
5x + 9 = 5 + 3x
Solution:
We have 5x + 9 = 5 + 3x
β 5x β 3x + 9 = 5 (Transposing 3x to LHS) => 2x + 9 = 5
β 2x = 5 β 9 (Transposing 9 to RHS)
β 2x = -4
β x = -4 Γ· 2 = -2
Hence x = -2 is the required solution.
Check: 5x + 9 = 5 + 3x
Putting x = -2, we have
LHS = 5 Γ (-2) + 9 = -10 + 9 = -1
RHS = 5 + 3 Γ (-2) = 5 β 6 = -1
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 4.
4z + 3 = 6 + 2z
Solution:
We have 4z + 3 = 6 + 2z
β 4z β 2z + 3 = 6 (Transposing 2z to LHS)
β 2z + 3 = 6
β 2z = 6 β 3 (Transposing 3 to RHS)
β 2z = 3
β z = [Math Processing Error]
Hence z = [Math Processing Error] is the required solution.
Check: 4z + 3 = 6 + 2z
Putting z = [Math Processing Error], we have
LHS = 4z + 3 = 4 Γ [Math Processing Error] + 3 = 6 + 3 = 9
RHS = 6 + 2z = 6 + 2 Γ [Math Processing Error] = 6 + 3 = 9
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 5.
2x β 1 = 14 β x
Solution:
We have 2x β 1 = 14 β x
β 2x + x = 14 + 1 (Transposing x to LHS and 1 to RHS)
β 3x = 15
β x = 15 Γ· 3 = 5
Hence x = 5 is the required solution.
Check: 2x β 1 = 14 β x
Putting x = 5
LHS we have 2x β 1 = 2 Γ 5 β 1 = 10 β 1 = 9
RHS = 14 β x = 14 β 5 = 9
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 6.
8x + 4 = 3(x β 1) + 7
Solution:
We have 8x + 4 = 3(x β 1) + 7
β 8x + 4 = 3x β 3 + 7 (Solving the bracket)
β 8x + 4 = 3x + 4
β 8x β 3x = 4 β 4 [Transposing 3x to LHS and 4 to RHS]
β 5x = 0
β x = 0 Γ· 5 [Transposing 5 to RHS]
or x = 0
Thus x = 0 is the required solution.
Check: 8x + 4 = 3(x β 1) + 7
Putting x = 0, we have
8 Γ 0 + 4 = 3(0 β 1) + 7
β 0 + 4 = -3 + 7
β 4 = 4
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 7.
x = [Math Processing Error] (x + 10)
Solution:
We have x = [Math Processing Error] (x + 10)
β 5 Γ x = 4(x + 10) (Transposing 5 to LHS)
β 5x = 4x + 40 (Solving the bracket)
β 5x β 4x = 40 (Transposing 4x to LHS)
β x = 40
Thus x = 40 is the required solution.
Check: x = [Math Processing Error] (x + 10)
Putting x = 40, we have
40 = [Math Processing Error] (40 + 10)
β 40 = [Math Processing Error] Γ 50
β 40 = 4 Γ 10
β 40 = 40
LHS = RHS
Hence verified.
Ex 2.3 Class 8 Maths Question 8.
[Math Processing Error] + 1 = [Math Processing Error] + 3
Solution:
We have [Math Processing Error] + 1 = [Math Processing Error] + 3
15([Math Processing Error] + 1) = 15([Math Processing Error] + 3)
LCM of 3 and 15 is 15
[Math Processing Error] Γ 15 + 1 Γ 15 = [Math Processing Error] Γ 15 + 3 Γ 15 [Multiplying both sides by 15]
β 2x Γ 5 + 15 = 7x + 45
β 10x + 15 = 7x + 45
β 10x β 7x = 45 β 15 (Transposing 7x to LHS and 15 to RHS)
β 3x = 30
β x = 30 Γ· 3 = 10 (Transposing 3 to RHS)
Thus the required solution is x = 10
Ex 2.3 Class 8 Maths Question 9.
2y + [Math Processing Error] = [Math Processing Error] β y
Solution:

Ex 2.3 Class 8 Maths Question 10.
3m = 5m β [Math Processing Error]
Solution:
We have











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