The chapter Aldehydes and Ketones is one of the most important topics in JEE NEET Chemistry, as it covers a wide variety of concepts, reactions, and applications in organic chemistry. Questions from this chapter are frequently asked in both competitive exams because they test a student’s understanding of nucleophilic addition reactions, oxidation–reduction, and the behavior of carbonyl compounds.

To help students prepare effectively, we have compiled 100 carefully selected MCQs on JEE NEET Chemistry Aldehydes Ketones with detailed solutions. These multiple-choice questions will not only strengthen your conceptual knowledge but also improve your speed, accuracy, and confidence for the exams.
JEE NEET Chemistry Aldehydes Ketones 100 MCQs with Answer Key
Questions with Answers (51–150)
Q51. Lactic acid on heating with conc. H₂SO₄ gives:
a) Acetic acid
b) Formic acid
c) Acrylic acid
d) Propionic acid
Answer: Acrylic acid (CH₂=CH–COOH) is formed when lactic acid undergoes dehydration with conc. H₂SO₄.
Q52. Urea can be detected by:
a) Benedict test
b) Molisch test
c) Ninhydrine test
d) Biuret test
Answer: Biuret test. Urea on heating decomposes to biuret, which gives a violet color with Cu²⁺ in alkaline medium.
Q53. Which of the following does not give brick red precipitate with Fehling’s solution?
a) Acetaldehyde
b) Formalin
c) D-glucose
d) Acetone
Answer: Acetone. Fehling’s solution is a test for aldehydes, ketones do not react.
Q54. Which of the following statements is wrong?
a) Formic acid is stronger than acetic acid
b) o-Bromobenzoic acid is weaker than o-chlorobenzoic acid
c) Lactic acid does not answer the silver mirror test
d) Benzaldehyde does not reduce Fehling’s solution
Answer: Statement (c) is wrong. Lactic acid does not have –CHO group, so it cannot give silver mirror test, but the framing makes it incorrect.
Q55. Pick out the reaction in which formic and acetic acid differ from each other:
a) Sodium replaces hydrogen from the compound
b) Forms esters with alcohols
c) Reduces ammoniacal silver nitrate or Fehling’s solution
d) Turns red litmus blue
Answer: Option (c). Formic acid reduces ammoniacal AgNO₃ and Fehling’s solution, but acetic acid does not.
Q56. An organic substance from its aqueous solution can be separated by:
a) Solvent extraction
b) Steam distillation
c) Distillation
d) Fractional distillation
Answer: Solvent extraction. It separates compounds based on differential solubility.
Q57. The strongest acid amongst the following compounds is:
a) CH₃COOH
b) HCOOH
c) CH₃CH₂CH(Cl)COOH
d) ClCH₂CH₂CH₂COOH
Answer: ClCH₂CH₂CH₂COOH. The –Cl atom increases acidity due to its –I effect.
Q58. What is obtained when acetyl chloride is heated with benzene in presence of anhydrous AlCl₃?
a) Acetyl benzoic acid
b) Anisol
c) Acetophenone
d) Chlorobenzene
Answer: Acetophenone. This is the classic Friedel–Crafts acylation reaction.
Q59. Reaction of formaldehyde and ammonia gives:
a) Hexamethylene tetramine
b) Bakelite
c) Urea
d) Triethylene tetramine
Answer: Hexamethylene tetramine (Urotropine).
Q60. 4-methyl benzene sulphonic acid reacts with sodium acetate to give:
Options incomplete in PDF, but the product is Toluene, formed through desulfonation reaction.
JEE NEET Chemistry Aldehydes Ketones 100 MCQs
Questions with Answers (51–150)
Q61. An acyl halide is formed when PCl₅ reacts with:
a) Acid
b) Alcohol
c) Amine
d) Ester
Answer: Acid. Carboxylic acids react with PCl₅ to give acyl chlorides.
Q62. Generally it is more difficult to purify organic compounds than inorganic compounds because:
a) They are very unstable
b) Their melting and boiling points are low
c) Organic compounds have low solubility
d) Physical constants of organic compounds and the impurities associated with them are very close to each other
Answer: Option (d). Organic compounds and impurities often have similar physical properties, making purification harder.
Q63. Acetophenone can be converted to ethylbenzene by reaction with:
a) LiAlH₄
b) H₂NOH
c) Pd–BaSO₄/H₂
d) Zn–Hg/HCl
Answer: Zn–Hg/HCl (Clemmensen’s reduction). It reduces the carbonyl group to –CH₂–.
Q64. When propionic acid is treated with aqueous sodium bicarbonate, CO₂ is liberated. The carbon of CO₂ comes from:
a) Methyl group
b) Carboxylic acid group
c) Methylene group
d) Bicarbonate
Answer: Carboxylic acid group. The –COOH group releases CO₂.
Q65. Boiling points of carboxylic acids are:
a) Lower than corresponding alcohols
b) Higher than corresponding alcohols
c) Equal to that of corresponding alcohols
d) None of the above
Answer: Higher than alcohols. This is due to stronger hydrogen bonding in acids (dimer formation).
Q66. The —COOH group in a carboxylic acid can be replaced by ‘H’ by heating the acid with:
a) Zn with HCl
b) H₂ in presence of nickel
c) Soda lime
d) Bromine and concentrated aqueous alkali
Answer: Soda lime. Decarboxylation with soda lime removes –COOH as CO₂.
Q67. The product obtained in the reaction (question incomplete in scan):
Options: a) b) c) d) There is no reaction
Answer: From context, the correct answer is No reaction (d).
Q68. Which of the following would produce a secondary alcohol?
a) Aldehyde + Grignard reagent
b) Ketone + Grignard reagent
c) Ester + Grignard reagent (excess)
d) Formaldehyde + Grignard reagent
Answer: Ketone + Grignard reagent. This yields a secondary alcohol.
Q69. Which factor(s) will increase the reactivity of >C=O group?
I. Presence of a group with positive inductive effect
II. Presence of a group with negative inductive effect
III. Presence of large alkyl group
a) Only (i)
b) Only (ii)
c) (i) and (iii)
d) (ii) and (iii)
Answer: Only (ii). An electron-withdrawing (–I) group increases carbonyl reactivity.
Q70. This reaction is called the:
a) Cannizzaro reaction
b) Schrodinger reaction
c) Hell–Volhard–Zelinsky reaction
d) Reimer–Tiemann reaction
Answer: Hell–Volhard–Zelinsky reaction (α-halogenation of carboxylic acids)
JEE NEET Chemistry Aldehydes Ketones 100 MCQs
Questions with Answers (51–150)
Q71. (CH₃)₂C=CH–COCH₃ can be oxidised to (CH₃)₂C=CH–COOH by:
a) Cu at 300 °C
b) KMnO₄
c) Chromic acid
d) NaOI
Answer: KMnO₄. It oxidises the ketone side chain to a carboxylic acid.
Q72. The correct order of decreasing boiling points of CH₃CONH₂ (A), CH₃COCl (B), CH₃COOH (C) and (CH₃CO)₂O (D) is:
a) A > D > C > B
b) A > B > C > D
c) D > C > B > A
d) None of these
Answer: A > C > D > B. Amides have highest boiling due to strong H-bonding, acid next, then anhydride, then acid chloride.
Q73. Rate of reaction is fastest when Z is:
a) Cl
b) NH₂
c) OC₂H₅
d) OCOCH₃
Answer: Cl. The –Cl group exerts a strong –I effect, increasing electrophilicity of carbonyl carbon.
Q74. Which is useful for separating benzoic acid from a mixture of benzoic acid and methyl benzoate?
a) NaHCO₃ (aq)
b) Dil. HCl
c) Dil. H₂SO₄
d) Dil. HNO₃
Answer: NaHCO₃ (aq). Benzoic acid dissolves as sodium benzoate, esters remain unaffected.
Q75. The compound X, in the reaction sequence is:
CH₃CHO → Y (hydrolysis) → Mg(OH)I + CH₃COOH
Options: a) CH₃CHO b) CO₂ c) (CH₃)₂CO d) HCHO
Answer: Formaldehyde (HCHO).
Q76. Which of the following does not undergo polymerization?
a) CH₃CHO
b) HCHO
c) CH₃COCH₃
d) None of these
Answer: CH₃COCH₃ (acetone).
Q77. The reaction RCOOAg + Br₂ → RBr + AgBr + CO₂ is called:
a) HVZ reaction
b) Hunsdiecker reaction
c) Hofmann’s reaction
d) Carbylamine reaction
Answer: Hunsdiecker reaction.
Q78. Methyl ketones are characterised through:
a) Tollen’s reagent
b) Iodoform test
c) Schiff’s test
d) Benedict’s reagent
Answer: Iodoform test (yellow ppt of CHI₃).
Q79. An organic compound X contains Y and Z impurities. Their solubility differs slightly. They may be separated by:
a) Simple crystallization
b) Fractional crystallization
c) Sublimation
d) Fractional distillation
Answer: Fractional crystallization.
Q80. Which of the following reactants on reaction with conc. NaOH followed by acidification gives a lactone as the product?
(Options incomplete in PDF)
Answer: Suitable cyclic ester forms, answer is lactone derivative.
Q81. An ester (A) with molecular formula C₉H₁₀O₂ was treated with excess of CH₃MgBr and the complex so formed was treated with H₂SO₄ to give an olefin (B). Ozonolysis of (B) gave a ketone with molecular formula C₈H₈O which shows positive iodoform test. The structure of (A) is:
a) C₆H₅COOC₂H₅
b) C₆H₅COOC₆H₅
c) C₆H₅COOCH₃
d) p-CH₃O–C₆H₄–COCH₃
Answer: C₆H₅COOCH₃ (methyl benzoate).
Q82. Acetone reacts with Grignard reagent to form:
a) 3° alcohol
b) 2° alcohol
c) Ether
d) No reaction
Answer: 3° alcohol.
Q83. When petroleum is heated gradually, first batch of vapours evolved will be rich in:
a) Kerosene
b) Petroleum ether
c) Diesel
d) Lubricating oil
Answer: Petroleum ether.
Q84. Decarboxylation of malonic acid gives:
a) CH₄
b) CH₃COOH
c) Both (a) and (b)
d) None of these
Answer: CH₃COOH (acetic acid).
Q85. What is the product in the reaction CH₃CONH₂ + NaOH/HCl → ?
a) CH₃COOH
b) CH₃CONH₃Cl
c) CH₃NH₂
d) CH₃CHO
Answer: CH₃NH₂.
Q86. Which of the following substances cannot be used for the replacement of —OH group in organic compounds by Cl?
a) S₂Cl₂
b) SOCl₂
c) PCl₃
d) PCl₅
Answer: S₂Cl₂.
Q87. Acetyl nitrate is formed when acetic anhydride reacts with:
a) Nitrogen pentoxide
b) Nitric acid
c) Nitrous acid
d) Potassium nitrate
Answer: Nitric acid.
Q88. Which one is not prepared from tartaric acid?
a) Tartar emetic
b) Fenton’s reagent
c) Fehling’s solution
d) Rochelle salt
Answer: Fenton’s reagent.
Q89. The reagent used in Clemmensen’s reduction is:
a) Conc. H₂SO₄
b) Zn–Hg/conc. HCl
c) aq. KOH
d) alc. KOH
Answer: Zn–Hg/conc. HCl.
Q90. In the reaction C₆H₅COOH + CH₃OH (H⁺) → Ester + water, isotopically labeled oxygen (O¹⁸) is present in:
a) Water
b) Ester
c) O¹⁸ shifts from acid to alcohol
d) No reaction takes place
Answer: Ester.
Q91. The technique of gas chromatography is suitable for compounds which are:
a) Liquids
b) Highly volatile
c) Soluble in water
d) Vaporise without decomposition
Answer: Highly volatile compounds.
Q92. There are several criteria of purity of organic compounds. Which is considered to be the best?
a) Melting point
b) Mixed melting point
c) Colour
d) Microscopic examination
Answer: Mixed melting point.
Q93. C₆H₅CHO + NH₃ → ? Product is:
a) —
b) C₆H₅CH=NH
c) —
d) —
Answer: C₆H₅CH=NH (imine).
Q94. The ease of hydrolysis with an alkali in the compounds CH₃COCl, CH₃CO–O–COCH₃, CH₃COOC₂H₅, CH₃CONH₂ is of the order:
a) I > II > III > IV
b) IV > III > II > I
c) I > II > IV > III
d) II > I > IV > III
Answer: I > II > III > IV.
Q95. What is the formula of adipic acid?
a) COOH(CH₂)₄COOH
b) CH₂(COOH)CH₂COOH
c) COOH(CH₂)₃COOH
d) None of the above
Answer: COOH(CH₂)₄COOH.
Q96. CH₃CHO and C₆H₅CH₂CHO can be distinguished chemically by:
a) Tollen’s reagent test
b) Fehling’s solution test
c) Benedict test
d) Iodoform test
Answer: Iodoform test. Acetaldehyde gives positive, benzaldehyde does not.
Q97. Acrolein on complete reduction gives:
a) Allyl alcohol
b) Propanol
c) Propanal
d) None of these
Answer: Propanol.
Q98. Identify the starting material of the following reaction:
(Options missing in scan)
Answer: Based on scheme → suitable aldehyde derivative.
Q99. Which one of the following is not a fatty acid?
a) Stearic acid
b) Palmitic acid
c) Oleic acid
d) Phenyl acetic acid
Answer: Phenyl acetic acid.
Q100. CH₃CN + H₂O → A → (with diazomethane) → B. A and B are:
a) Acetamide, N-methyl acetamide
b) Acetic acid, ethyl ethanoate
c) Acetic acid, methyl acetate
d) Acetamide, acetone
Answer: Acetic acid, methyl acetate.
JEE NEET Chemistry Aldehydes Ketones 100 MCQs
Questions with Answers (51–150)
Q101. In iodoform test, the active species is:
a) I₂
b) I⁺
c) I₃⁻
d) HIO
Answer: I⁺. The electrophilic iodine reacts with the methyl ketone group.
Q102. Propionic acid on treatment with Br₂ and P red gives:
a) 2-Bromopropionic acid
b) 3-Bromopropionic acid
c) Bromoethane
d) 2,2-Dibromopropanoic acid
Answer: 2-Bromopropionic acid (Hell–Volhard–Zelinsky reaction).
Q103. Which one of the following is most acidic?
a) Phenol
b) Benzoic acid
c) Benzyl alcohol
d) Acetophenone
Answer: Benzoic acid. The –COOH group is strongly acidic.
Q104. The product obtained when acetone is treated with Zn–Hg/HCl is:
a) Methane
b) Ethane
c) Propane
d) Butane
Answer: Propane. (Clemmensen’s reduction of acetone).
Q105. Which of the following gives positive iodoform test?
a) Benzophenone
b) Acetophenone
c) Formaldehyde
d) Acetaldehyde
Answer: Acetophenone and acetaldehyde. Both have CH₃–CO– group.
Q106. The major product formed when acetaldehyde is treated with concentrated NaOH at room temperature is:
a) Acetic acid
b) Ethanol
c) Aldol (β-hydroxybutanal)
d) Acetone
Answer: Aldol (β-hydroxybutanal). This is aldol condensation.
Q107. The acidity of carboxylic acids is due to:
a) Strong C–H bond
b) Weak O–H bond
c) Resonance stabilization of carboxylate ion
d) High electronegativity of carbon
Answer: Resonance stabilization of carboxylate ion.
Q108. Which one of the following compounds will give effervescence with NaHCO₃ solution?
a) Ethanol
b) Glucose
c) Acetic acid
d) Acetone
Answer: Acetic acid. Carboxylic acids react with NaHCO₃ to liberate CO₂.
Q109. When benzaldehyde is heated with conc. NaOH, the products formed are:
a) Benzoic acid and benzyl alcohol
b) Benzyl alcohol and phenol
c) Benzyl alcohol and toluene
d) Benzyl alcohol only
Answer: Benzoic acid and benzyl alcohol (Cannizzaro reaction).
Q110. The reaction between acetyl chloride and benzene in presence of AlCl₃ is known as:
a) Friedel–Crafts alkylation
b) Friedel–Crafts acylation
c) Cannizzaro reaction
d) Perkin’s reaction
Answer: Friedel–Crafts acylation.
Q111. Which of the following compounds will not reduce Fehling’s solution?
a) Formaldehyde
b) Acetaldehyde
c) Benzaldehyde
d) Glucose
Answer: Benzaldehyde. Aromatic aldehydes generally do not reduce Fehling’s solution.
Q112. Oxidation of acetone with alkaline KMnO₄ produces:
a) Acetic acid + Formic acid
b) Acetic acid + CO₂
c) Acetic acid only
d) Propanoic acid
Answer: Acetic acid + Formic acid.
Q113. Which of the following acids is the strongest?
a) Acetic acid
b) Chloroacetic acid
c) Formic acid
d) Trichloroacetic acid
Answer: Trichloroacetic acid. Multiple –Cl atoms increase acidity strongly.
Q114. Reduction of acetic acid with LiAlH₄ gives:
a) Ethane
b) Ethanol
c) Acetaldehyde
d) Propanol
Answer: Ethanol.
Q115. The product of reaction between acetaldehyde and hydroxylamine is:
a) Aldoxime
b) Ketoxime
c) Oxime ether
d) Hydrazone
Answer: Aldoxime.
Q116. Which of the following will give Cannizzaro reaction?
a) Formaldehyde
b) Acetaldehyde
c) Acetone
d) Butanone
Answer: Formaldehyde. (Aldehydes without α-hydrogen give Cannizzaro reaction).
Q117. Acetone on oxidation with K₂Cr₂O₇/H₂SO₄ gives:
a) Acetic acid + Formic acid
b) Acetic acid only
c) Propanoic acid
d) Oxalic acid
Answer: Acetic acid + Formic acid.
Q118. Which of the following aldehydes undergoes Cannizzaro reaction?
a) Acetaldehyde
b) Formaldehyde
c) Benzaldehyde
d) Both (b) and (c)
Answer: Both (b) and (c).
Q119. When acetaldehyde is heated with KOH and iodine, the product is:
a) Chloroform
b) Iodoform
c) Ethanol
d) Acetic acid
Answer: Iodoform (yellow precipitate).
Q120. Which of the following statements is true?
a) Aldehydes are less reactive than ketones
b) Aldehydes are more reactive than ketones
c) Both are equally reactive
d) None
Answer: Aldehydes are more reactive than ketones, due to less steric hindrance and less +I effect.
Q121. Reaction of benzaldehyde with acetic anhydride in presence of sodium acetate is known as:
a) Perkin’s reaction
b) Aldol condensation
c) Friedel–Crafts acylation
d) Cannizzaro reaction
Answer: Perkin’s reaction.
Q122. Which of the following gives positive Tollen’s test?
a) Acetone
b) Benzaldehyde
c) Acetophenone
d) Acetone oxime
Answer: Benzaldehyde.
Q123. The reaction of an aldehyde with two equivalents of a monohydric alcohol in presence of dry HCl gas gives:
a) Acetal
b) Hemiacetal
c) Ester
d) Ether
Answer: Acetal.
Q124. Acetone on treatment with semicarbazide gives:
a) Semicarbazone
b) Hydrazone
c) Oxime
d) Imine
Answer: Semicarbazone.
Q125. Which of the following is least reactive towards nucleophilic addition?
a) Formaldehyde
b) Acetaldehyde
c) Benzaldehyde
d) Acetone
Answer: Benzaldehyde (due to resonance stabilization and lower reactivity).
Q126. Which one of the following does not give iodoform test?
a) Acetone
b) Acetaldehyde
c) Ethanol
d) Formaldehyde
Answer: Formaldehyde.
Q127. Acetaldehyde reacts with NH₃ to form:
a) Hexamethylenetetramine
b) Aldimine
c) Schiff’s base
d) Acetaldoxime
Answer: Aldimine (CH₃CH=NH).
Q128. Which of the following does not give Cannizzaro reaction?
a) Formaldehyde
b) Benzaldehyde
c) Acetaldehyde
d) Trimethylacetaldehyde
Answer: Acetaldehyde (since it has α-hydrogen).
Q129. Which of the following reduces Fehling’s solution?
a) Formaldehyde
b) Acetaldehyde
c) Benzaldehyde
d) Both (a) and (b)
Answer: Both (a) and (b).
Q130. Acetone reacts with HCN in presence of KCN to give:
a) Cyanohydrin
b) Oxime
c) Amide
d) Amine
Answer: Cyanohydrin.
Q131. Which one is the most reactive carbonyl compound?
a) Formaldehyde
b) Acetaldehyde
c) Benzaldehyde
d) Acetone
Answer: Formaldehyde.
Q132. Oxidation of ethanol with acidified KMnO₄ gives:
a) Acetaldehyde
b) Acetic acid
c) Formaldehyde
d) Formic acid
Answer: Acetic acid.
Q133. Which reagent distinguishes between aldehydes and ketones?
a) Fehling’s solution
b) Tollen’s reagent
c) Both (a) and (b)
d) None
Answer: Both (a) and (b).
Q134. Reduction of acetone by NaBH₄ gives:
a) Ethanol
b) Isopropanol
c) Propanol
d) Methanol
Answer: Isopropanol (2-propanol).
Q135. Acetaldehyde undergoes aldol condensation to give:
a) 3-hydroxybutanal
b) Crotonaldehyde
c) Acetic acid
d) Acetone
Answer: 3-hydroxybutanal.
Q136. In the Cannizzaro reaction, the reducing agent is:
a) Aldehyde itself
b) Alcohol
c) Alkali
d) Water
Answer: Aldehyde itself.
Q137. Which one of the following is an α-hydroxy acid?
a) Lactic acid
b) Oxalic acid
c) Acetic acid
d) Formic acid
Answer: Lactic acid.
Q138. Formaldehyde reacts with NH₂OH to form:
a) Oxime
b) Aldoxime
c) Ketoxime
d) Schiff base
Answer: Oxime (formaldoxime).
Q139. Acetic acid reacts with PCl₅ to form:
a) Acetyl chloride
b) Acetone
c) Acetaldehyde
d) Acetic anhydride
Answer: Acetyl chloride.
Q140. Benzaldehyde undergoes Cannizzaro reaction in presence of:
a) Conc. HCl
b) Conc. NaOH
c) Dil. H₂SO₄
d) ZnCl₂
Answer: Conc. NaOH.
Q141. Which of the following compounds undergoes aldol condensation?
a) Acetaldehyde
b) Formaldehyde
c) Benzaldehyde
d) Trimethylacetaldehyde
Answer: Acetaldehyde.
Q142. Formaldehyde reacts with ammonia to give:
a) Urotropine
b) Semicarbazone
c) Oxime
d) Schiff base
Answer: Urotropine (hexamethylenetetramine).
Q143. Reduction of acetone with Zn–Hg/HCl gives:
a) Ethane
b) Propane
c) Butane
d) Methane
Answer: Propane.
Q144. Which compound will not give Cannizzaro reaction?
a) HCHO
b) C₆H₅CHO
c) CH₃CHO
d) p-NO₂C₆H₄CHO
Answer: CH₃CHO.
Q145. The product of reaction between acetic acid and ethanol in presence of conc. H₂SO₄ is:
a) Acetaldehyde
b) Acetone
c) Ethyl acetate
d) Acetyl chloride
Answer: Ethyl acetate (esterification).
Q146. Which of the following acids is strongest?
a) Formic acid
b) Acetic acid
c) Chloroacetic acid
d) Trichloroacetic acid
Answer: Trichloroacetic acid.
Q147. Oxidation of acetaldehyde with KMnO₄ gives:
a) Acetic acid
b) Acetone
c) Methanol
d) Formic acid
Answer: Acetic acid.
Q148. Acetone on reaction with phenylhydrazine gives:
a) Phenylhydrazone
b) Semicarbazone
c) Oxime
d) Hydrazine
Answer: Phenylhydrazone.
Q149. Benzaldehyde reacts with HCN to give:
a) Benzyl alcohol
b) Benzyl cyanide
c) Benzylidene cyanohydrin
d) Benzoic acid
Answer: Benzylidene cyanohydrin.
Q150. Oxidation of formaldehyde with Tollen’s reagent gives:
a) Formic acid
b) CO₂ + H₂O
c) Methanol
d) Acetic acid
Answer: Formic acid.
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- Morphology of Flowering Plants
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- NCERT Textbooks (for Class 10):