Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3 NCERT Solution

In Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3, we learn how to find the nature of the roots of quadratic equations. The nature of the roots depends on the value of the discriminant (Δ=b2−4ac).

  • If Δ>0 the equation has two distinct real roots.
  • If Δ=0, the equation has two equal real roots.
  • If Δ<0 the equation has no real roots.

This exercise helps us determine the type of roots of a quadratic equation based on the discriminant, without needing to solve the equation completely. It is an important concept for understanding the behavior of quadratic equations in various situations.

Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3

Question 1.
Find the roots of the following quadratic equations, if they exist, by the method of completing the square:
(i) 2x2 – 7x + 3 = 0
(ii) 2x2 + x – 4 = 0
(iii) 4x2 + 4√3x + 3 = 0
(iv) 2x2 + x + 4 = 0
Solution:
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 Free PDF Download Q1
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 PDF Q1.1
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 Q1.2

Question 2.
Find the roots of the quadratic equations by applying the quadratic formula.
(i) 2x2 – 7x + 3 = 0
(ii) 2x2 – x + 4 = 0
(iii) 4x2 – 4√3x + 3 = 0
(iv) 2x2 – x + 4 = 0
Solution:

Ex 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations PDF Download Q2
Ex 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations PDF Q2.1
Ex 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations Q2.2

Question 3.
Find the roots of the following equations:

NCERT Solutions For Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3 Q1

NCERT Solutions For Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3 Q2
Solution:
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.3 Q3
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Q3.1

Ex 4.3 Class 10 | Maths NCERT Solutions for Class 10 Maths Chapter 4 | Quadratic Equations Ex 4.3

Question 4.
The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 13 Find his present age.
Solution:

Chapter 4 Maths Class 10 NCERT Solutions Exercise 4.3 PDF Download Q4

Question 5.
In a class test, the sum of Shefali’s marks in Mathematics and English is 30. Had she got 2 marks more in Mathematics and 3 marks less in English, the product of their marks would have been 210. Find her marks in the two subjects.
Solution:

Chapter 4 Maths Class 10 NCERT Solutions Exercise 4.3 PDF Q5

Question 6.
The diagonal of a rectangular field is 60 metres more than the shorter side. If the longer side is 30 metres more than the shorter side, find the sides of the field.
Solution:

Chapter 4 Maths Class 10 NCERT Solutions Exercise 4.3 Q6

Question 7.
The difference of squares of two numbers is 180. The square of the smaller number is 8 times the larger number. Find the two numbers.
Solution:

Exercise 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations Free PDF Q7
Exercise 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations Q7.1

Question 8.
A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train.
Solution:

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.2 Q8

Question 9.
Two water taps together can fill a tank in 938 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.
Solution:

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Exercise 4.2 PDF Q9
NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Q9.1

Question 10.
An express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bengaluru (without taking into consideration the time they stop at intermediate stations). If the average speed of the express train is 11 km/h more than that of the passenger train, find the average speed of the two trains.
Solution:

Ex 4.3 Class 10 Maths NCERT Solutions Chapter 4 Quadratic Equations Q10

Question 11.
Sum of the areas of two squares is 468 m2. If the difference of their perimeters is 24 m, find the sides of the two squares.
Solution:

Chapter 4 Maths Class 10 NCERT Solutions Exercise 4.3 PDF Q11
Chapter 4 Maths Class 10 NCERT Solutions Exercise 4.3 PDF Download Q11.1

New Syllabus – Class 10 Maths Chapter 4 Quadratic Equations Ex 4.3

Question 1: Find the nature of the roots of the following quadratic equations. If real roots exist, find them:

(i) 2x² – 3x + 5 = 0

Solution:

For the quadratic equation 2x² – 3x + 5 = 0, we have:

  • a = 2
  • b = -3
  • c = 5

The discriminant (Δ) is:

Δ = b² – 4ac = (-3)² – 4(2)(5) = 9 – 40 = -31

Since Δ < 0, the equation has no real roots.

(ii) 3x² – 4x + 4 = 0

Solution:

For the quadratic equation 3x² – 4x + 4 = 0, we have:

  • a = 3
  • b = -4
  • c = 4

The discriminant (Δ) is:

Δ = b² – 4ac = (-4)² – 4(3)(4) = 16 – 48 = -32

Since Δ < 0, the equation has no real roots.

(iii) 2x² – 6x + 3 = 0

Solution:

For the quadratic equation 2x² – 6x + 3 = 0, we have:

  • a = 2
  • b = -6
  • c = 3

The discriminant (Δ) is:

Δ = b² – 4ac = (-6)² – 4(2)(3) = 36 – 24 = 12

Since Δ > 0, the equation has two distinct real roots.

To find the roots, we use the quadratic formula:

x = (-b ± √Δ) / 2a

x = (-(-6) ± √12) / 2(2) = (6 ± 2√3) / 4 = (3 ± √3) / 2

Thus, the roots are:

x = (3 + √3) / 2 or x = (3 – √3) / 2

Question 2: Find the values of k for each of the following quadratic equations, so that they have two equal roots.

(i) 2x² + kx + 3 = 0

Solution:

For the quadratic equation 2x² + kx + 3 = 0, the condition for two equal roots is that the discriminant Δ = 0.

The discriminant is:

Δ = b² – 4ac

Here, a = 2, b = k, and c = 3, so:

Δ = k² – 4(2)(3) = k² – 24

For two equal roots, Δ = 0:

k² – 24 = 0

k² = 24

k = ±√24 = ± 2√6

Thus, the values of k are k = 2√6 or k = -2√6.

(ii) kx(x – 2) + 6 = 0

Solution:

First, expand the equation:

kx(x – 2) + 6 = 0 → kx² – 2kx + 6 = 0

For this quadratic equation to have two equal roots, the discriminant must be zero. So:

Δ = b² – 4ac = 0

Here, a = k, b = -2k, and c = 6. The discriminant is:

Δ = (-2k)² – 4(k)(6) = 4k² – 24k

For two equal roots, Δ = 0:

4k² – 24k = 0

4k(k – 6) = 0

Thus, k = 0 or k = 6.

Therefore, the values of k are k = 0 or k = 6.

You can access the official NCERT Solutions for Class 10 Mathematics on the NCERT website at the following link:

NCERT Class 10 Mathematics Solutions

This page will guide you to the textbook and solutions, as provided by the National Council of Educational Research and Training (NCERT).

You can access the official NCERT Solutions for Class 10 Mathematics on the NCERT website at the following link:

NCERT Class 10 Mathematics Solutions

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